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katrin [286]
3 years ago
15

The number of students enrolled at a community

Mathematics
1 answer:
LenKa [72]3 years ago
7 0
Please include a picture!!!!
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What number can go into 68 and 100
Sati [7]
One number is 4 Another is 2 I hope this helped
8 0
3 years ago
Read 2 more answers
Solve the LP problem. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is
Volgvan

Answer:

(x,y)=(0,7.333)

Step-by-step explanation:

We are required to:

Maximize p = x + 2y subject to

  • x + 3y ≤ 22
  • 2x + y ≤ 14
  • x ≥ 0, y ≥ 0.

The graph of the lines are plotted and attached below.

From the graph, the vertices of the feasible region are:

  • (0,7.333)
  • (4,6)
  • (0,0)
  • (7,0)

At (0,7.333), p=0+2(7.333)=14.666

At (4,6), p=4+2(6)=4+12=16

At (0,0), p=0

At (7,0), p=7+2(0)=7

Since 14.666 is the highest, the maximum point of the feasible region is (0,7.333).

At x=0 and y=7.333, the function p is maximized.

7 0
3 years ago
9 t-shirts and a hat costs £93 4 t-shirts and a hat costs £43 how much does the hat and t-shirt cost
alexandr402 [8]

Answer:

T-shirt costs £10

Hat costs £3

Step-by-step explanation:

£93-£43=£50

9-4=5

£50/5=10

1 t-shirt=£10

£10x9=£90

£93-£90=£3

T-shirt = £10

Hat= £3

4 0
3 years ago
Read 2 more answers
If Mitzi has two dogs, a puppy that weighs 25 pounds and an adult that weighs 80 pounds, how much will it cost to bathe them bot
Sidana [21]

Answer:

The correct answer is A) $105

Step-by-step explanation:

In this real-world problem,  the cost to groom both dogs is (the puppy) + (the adult dog) = x.

For the first step, y = 40, if x <= 25.

y = 50, if 25 < x < 50.

if x >= 50, then y = 0.50x + 25

So therefore, substitute the puppy + adult dog = x

25 + 80 = x

105 = x

So, the final answer is $105.

It's on Edgen.

4 0
3 years ago
What is the interquartile range of this set of data? 15,19,20,25,31,38,41
cupoosta [38]

Answer: 19.

Step-by-step explanation:

1: Place your numbers in numerical order from smallest to largest; 15,19,20,25,31,38,41.

2. Find your median in the set of numbers; 15,19,20,25,31,38,41.

3. Find Q1 and Q3 in your set of numbers by placing parentheses around the median you have just found. (15,19,20),25,(31,38,41.)

4. In this instance, you need to find the medians of the two number sets in parentheses; (15,19,20),  19 being Q1, and (31,38,41), 38 being Q3.

5. Using the interquartile range formula; Q3-Q1= IQR, plug in your numbers.

38-19=19, making the answer 19.

7 0
3 years ago
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