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gayaneshka [121]
3 years ago
6

9.A couple just had twin boys, but they can't decide between the names Mike, Mark, Peter, Paul, Sam, and Sonny. If the couple ra

ndomly chooses names for the 2 boys from the names listed, what is the probability that the first boy born will be named Sam and the second boy born will be named Mark? Assume that the boys will not have the same name.
For question 9, what is the probability that one of the boys will be named Peter and the other boy will be named Paul?
Mathematics
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

The first answer is 1/3 the second answer is also 1/3

Step-by-step explanation:

If you count the number of names there are and take two out that would round down from 2/6 to 1/3. The answer is the same for both questions.

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Given that ∠A and ∠B are supplementary, Daisy conjectured that ∠A≅∠B . Which statement is a counterexample to Daisy's conjecture
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I believe the answer is C. 40 and 140.

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3 years ago
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Carter is solving for x by the process of completing the square for the following
Ksenya-84 [330]

Answer:

The number that goes in place of the question mark is 2.

Step-by-step explanation:

Let's solve it!

3x² + 12x - 24 = 0

First we can factor 3 out of each term:

x² + 4x - 8 = 0

Now we'll add 12 to both sides to complete the square:

x² + 4x + 4 = 12

And finish it off:

(x + 2)² = 12

So the answer to the question is 2

Bonus:

We can also now solve this for x:

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x = √12 - 2

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3 0
2 years ago
The diagram shows a triangle.<br><br> What is the value of z?
Damm [24]

Answer:

z=31°

Step-by-step explanation:

32°+117°+z=180°{ sum of angle of triangle}

z=180-149

z=31°

<h2>stay safe healthy and happy.</h2>
6 0
3 years ago
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What are the rules for these problems?
Rudiy27
The answer to number 3 is -12 because you would do X times 4 and then add 8

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4 0
3 years ago
Simplify the radical 7√7-2√28
Umnica [9.8K]

ANSWER

3 \sqrt{7}

EXPLANATION

The given radical is

7 \sqrt{7}  - 2 \sqrt{28}

Remove the perfect square from the second radical.

= 7 \sqrt{7}  - 2 \sqrt{4 \times 7}

= 7 \sqrt{7}  - 2 \sqrt{4}  \times  \sqrt{7}

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= 7 \sqrt{7}  - 4 \sqrt{7}

Subtract the like radicals

= 3 \sqrt{7}

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2 years ago
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