1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
3 years ago
7

Enter the equation of the line in slope-intercept form.

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0

Answer:

y - 5 = 3(x - 4)

y - 5 = 3x - 12

y = 3x - 7

Step-by-step explanation:

You might be interested in
−2t−5&lt;9<br><br> Hiiiiiiii<br><br> Huuuu
Brilliant_brown [7]

Answer:

t > -7

Step-by-step explanation:

To solve for t, first add 5 to both sides:

-2t - 5 < 9

-2t < 14

Divide each side by -2, and flip the inequality because we are dividing by a negative number:

-2t < 14

t > -7

So, the solution is t > -7

4 0
3 years ago
Read 2 more answers
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
Plzzzzzzzzzzzzzzzzzz
valina [46]

Answer:

successful odds are a and c

7 0
3 years ago
Read 2 more answers
The formula F=9/5 x C + 32 can be used to find the temperature in F degrees of a temperature of C. Which is an equivalent to 35
wolverine [178]

Answer:

The answer is C: 95° Celsius

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which number completes the inequality?
aliya0001 [1]
The answer to it would be C.
5 0
3 years ago
Other questions:
  • On Monday, Zach sends an e-mail message
    9·1 answer
  • Simplfy 8 /18 i need help!
    7·2 answers
  • Simplify to create an equivalent expression.<br> 2(3y+6)-3(-4-y)
    13·1 answer
  • Lana will sew 2 blankets for each of her grandchildren. write an equation to represent how many blankets (b) Lana will sew for (
    11·2 answers
  • Complete the equation. Round to the nearest hundredth where necessary.
    8·1 answer
  • Adding parentheses and brackets
    12·1 answer
  • Can someone please help me with my homework
    10·1 answer
  • (BRAINLIEST)PLEASE HELP ASAP!!
    8·1 answer
  • the following are the heights in centimeters of 15 randomly selected students. Find the mean height of the students.
    10·2 answers
  • -6-4+[-4] 0 [-4-[-3]]<br> [4² + 3²] ÷ 5
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!