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2 years ago

I need help with number 18

Mathematics

1 answer:

Zina [86]2 years ago

3 0

Answer:

Step-by-step explanation:

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The rectangle below has an area of x² – 6x – 7 square meters and a width of 3 – 7 meters.

natta225 [31]

Answer:

The expression which represent the length of the rectangle is x + 1

Step-by-step explanation:

Given as :

The Area of rectangle = x² - 6 x - 7 square meters

The width of the rectangle = w = x - 7 meters

Let The length of rectangle = L meters

Now, <u>According to question</u>

∵ Area of Rectangle = Length × width

or, x² - 6 x - 7 meters² = L meters × w meters

or, x² - 6 x - 7 = L × (x - 7)

or, x² - 7 x + x - 7 = L × (x - 7)

or, x (x - 7) + 1 (x - 7) = L × (x - 7)

or, (x - 7) (x + 1) = L × (x - 7)

∴ L = $\frac{(x - 7)\times (x + 1)}{(x - 7)}$

I,e L = x + 1

So, The length of rectangle = L = x + 1

Hence,The expression which represent the length of the rectangle is x + 1 Answer

8 0

2 years ago

The volume of this cone is 36π cubic units.

kap26 [50]

Answer:

108pi

Step-by-step explanation:

We do not need to know the height and radius, as the formula for the volume of a cone is just a third of the volume of a cylinder. So we have 36pi * 3 or 108pi.

4 0

2 years ago

The minimum value of Y in the equation y = x2 - 6x + 8

murzikaleks [220]

Given

$y=x^2-6x+8$

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

$y^{\prime}=2x-6$

Equating

$y^{\prime}\text{ = 0}$

gives the minimum value we require.

Doing that, we have:

$2x-6=0$

So that

$\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}$

Therefore, the minimum value is x = 3

8 0

1 year ago

Seven blue and four red balls are to be arranged in order. How many ways can this be done if (1) The blue balls are distinguisha

Sav [38]

Answer:

1) n = 39916800

2) n = 1663200

3) n = 330

Step-by-step explanation:

1) If the blue balls are distinguishable as are the red balls

Then you can arrange these balls in the following ways, we must use a permutation

In totally we have 11 balls, then

n = 11P11

$n = \frac{11!}{(11-11)!} = 11! = 39916800\\$

2) If Blue balls are distinguishable, but the red balls are identical

In this case, we need to do a correction due to the red balls are identical and we cannot identify the difference when we interchange two red balls

$n = \frac{11!}{4!} = \frac{39916800}{24} = 1663200$

3) If the balls of each color are indistinguishable

We proceed equal to the before case but we include a correction due to blue balls also

$n = \frac{11!}{4!*7!} = \frac{39916800}{24*5040} = 330$

7 0

2 years ago

30 points! please help

Trava [24]

Gopherus have been clocked at rates 0.13 to 0.30 mph (0.05 to 0.13 m/s

5 0

3 years ago