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3 years ago

Find a Cartesian equation for the curve and identify it. r=8tanxsecx

1 answer:

3 0

R = 8 tan(x) sec(x)

In order to solve this, we are going to use the following:
r = sqrt(x^2 + y^2) //but in this case, we don't need this.
tan(x) = Y / X
X = r cos(x)
Y = r sin(x)

<span>(r cos x)^2 = 8(r sin x)</span>

x^2 = 8y

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Pls help this is urgent

ozzi

Answer:

Step-by-step explanation:

im passing this concept trust me the answer is 12

5 0

2 years ago

What is the domain of \sqrt{4-6a}? PLS ANSWER SOON DUE TMRW

Igoryamba

Answer:

(−∞,2/3],{a∣a≤2/3}

<h2>Step-by-step explanation:</h2>

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8 0

3 years ago

The sides of a square all have a side length of y. Write a simplified area function in terms of y for a rectangle whose length i

gizmo_the_mogwai [7]

The simplified area function in terms of y for a rectangle is $f(y)=2 y^{2}+4 y$

<u>Solution:</u>

Given that length of each side of a square = y

Need to determine area of rectangle whose length is twice the length of the square and width is 2 units longer that the side length of square

Length of rectangle = twice of side length of square = $2 \times y = 2y$

Width of rectangle = 2 + side length of square = 2 + y = y + 2

$\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle.}$

On substituting length and width in formula for area, we get

$\text { Area of rectangle }=2 y \times (y+2)=2 y^{2}+4 y$

Hence function $f(y)=2 y^{2}+4 y$ is represents area of required rectangle.

3 0

3 years ago

A quantity with an initial value of 8100 grows exponentially at a rate of 0.35% every 4

vazorg [7]

Answer:

8133.38

Step-by-step explanation:

Given that :

Initial value, P = 8100

Growth rate = 0.35% every 4 decade = 0.35% /40 = 0.0000875 per year

Quantity after 47 years

Using the relation :

A = P*e^(rt)

Amount after t years

t = 47 years

A = 8100 * e^(0.0000875*47)

A = 8100 * e^0.0041125

A = 8100 * 1.0041209

A = 8133.3798

A = 8133.38 (nearest hundredth)

6 0

3 years ago

Given f(x) = 52x, evaluate f-1), f(o), and K2).<br><br> 01/25, 1, 625

lbvjy [14]

Answer:

$f(-1) = \frac{5}{2}$

$f(0) = 5$

$f(2) = 20$

Step-by-step explanation:

Given

$f(x) = 5(2^x)$

Required

Determine f(-1); f(0) and f(2)

Solving f(-1)

In this case, we simply take x as;

$x = -1$

Substitute -1 for x in $f(x) = 5(2^x)$

$f(-1) = 5(2^{-1})$

Apply law of indices

$f(-1) = 5 * \frac{1}{2}$

$f(-1) = \frac{5}{2}$

Solving f(0)

In this case, we simply take x as;

$x = 0$

Substitute 0 for x in $f(x) = 5(2^x)$

$f(0) = 5(2^0)$

$f(0) = 5(1)$

$f(0) = 5$

Solving f(2)

In this case, we simply take x as;

$x = 2$

Substitute 2 for x in $f(x) = 5(2^x)$

$f(2) = 5(2^2)$

$f(2) = 5(4)$

$f(2) = 20$

4 0

4 years ago