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3 years ago

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A computer technician charges a flat rate for home vist plus $55 per hour. The technician bills $190 for a 2-hour home vist to i

nstall a new hard drive. The equation y-190=55(x-2) gives the total amount y the technician charges for x hour of work. What is the equation in slope-intercept form?

2 answers:

djyliett [7]3 years ago

4 0

Y - 190 = 55(x - 2)....distribute thru the parenthesis
y - 190 = 55x - 110....now add 190 to both sides
y = 55x - 110 + 190..simplify
y = 55x + 80 <== slope intercept form (y = mx + b)

Masteriza [31]3 years ago

3 0

Answer:

<em>The equation in slope-intercept form will be: $y=55x+80$ </em>

Step-by-step explanation:

The given equation is: $y-190=55(x-2)$

The standard slope-intercept form is $y=mx+b$

Simplifying the given equation..........

$y-190=55(x-2)\\ \\ y-190=55x-110\ \ \ [using\ distributive\ property\ in\ right\ side]\\ \\ y-190+190=55x-110+190 \ \ \ [adding\ 190\ both\ sides]\\ \\ y=55x+80\ \ \ [combining\ like\ terms]$

<em>This equation is in form of $y=mx+b$ </em>

So, the equation in slope-intercept form will be: $y=55x+80$

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Solve x/-3 = -15.<br><br> A.) -45<br> B.) 5<br> C.) -5<br> D.) 45<br> this is multiple choice

Fiesta28 [93]

Answer:

x= 45

Step-by-step explanation:

x= -15*-3

x= 45

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3 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

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Here is a list of numbers:<br> 3,16, 7, 19, 1, 12, 3,9,16,12<br> State the median.

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Dafna11 [192]

Answer:

The horsepower required is 235440 watt.

Step-by-step explanation:

To find : What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?

Solution :

The horsepower formula is given by,

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Where, W is the horsepower

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Substitute all values in the formula,

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