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iVinArrow [24]
3 years ago
14

The data given below consists of the number of children with food allergies at a sample of elementary schools: 3, 9, 5, 5, 14, 1

0, 5, 11, 9, 6, 1, 8, 10, 7, 9, 13, 18, 9, 8, 11, 9, 7, 6, 14, 12. Find the z-score corresponding to the median of school allergies. You may use your calculator to find the mean and standard deviation.
Mathematics
1 answer:
Mice21 [21]3 years ago
4 0

Answer:

z -score = 0.0459

Step-by-step explanation:

Given that:

the number of children with food allergies at a sample of elementary schools: 3, 9, 5, 5, 14, 10, 5, 11, 9, 6, 1, 8, 10, 7, 9, 13, 18, 9, 8, 11, 9, 7, 6, 14, 12.

The objective is to find the z- score , but before we can do that , we need to determine the mean and the standard deviation of the sample.

Mean = sum of the sample/ total number of the sample

Mean = (3+9+ 5+ 5+ 14+ 10+ 5+ 11+ 9+ 6+ 1+ 8+ 10+ 7+ 9+13+ 18+ 9+ 8+11+ 9+ 7+ 6+ 14+ 12)/25

Mean = 219/25

Mean = 8.76

Standard deviation = \sqrt{\dfrac {\sum (x_i - \mu)^2}{N}}

Mean (in order )= 1, 3,5,5,5,6,6,7,7,8,8,9,9,9,9,9,10,10,11,11,12,13,14,14,18)

Standard deviation = \sqrt{\dfrac { (8.76 - 1)^2}{25} + \dfrac { (8.76 - 3)^2}{25} +\dfrac { (8.76 - 5)^2}{25} +...+ \dfrac { (8.76 - 18)^2}{25}   }

Standard deviation = 5.2174

The standard z score formula is:

z = \dfrac{X- \mu}{\sigma}

where X = median (13th observation ) = 9

z = \dfrac{9- 8.76}{5.2174}

z = \dfrac{0.24}{5.2174}

z -score = 0.0459

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$17,818 is invested, part at 11% and the rest at 6%. If the interest earned from the amount invested at 11% exceeds the interest
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Answer:We know the total amount of money invested. $17818

x+y=17818,

We know that the difference in interest earned by the two accounts is $490.33

0.11*x-0.06*y=490.33

x=17818-y

We substitute for x

0.11*(17818-y)-0.06*y=490.33

We multiply out

1959.98-0.11y-0.06*y=490.33

We combine like terms.

1469.65=0.17*y

Isolate y

y=1469.65/0.17

y=8645 at 6%

Calculate x

x=17818-8645

x=9173 at 11%

Check

0.11*9173-0.06*8645=490.33

interest earned at 11%=1009.03

interest earned at 6%=518.70

1009.03-518.7=490.33

490.33=490.33

Since this statement is TRUE and neither amount is negative then all is well.We know the total amount of money invested. $17818

x+y=17818,

We know that the difference in interest earned by the two accounts is $490.33

0.11*x-0.06*y=490.33

x=17818-y

We substitute for x

0.11*(17818-y)-0.06*y=490.33

We multiply out

1959.98-0.11y-0.06*y=490.33

We combine like terms.

1469.65=0.17*y

Isolate y

y=1469.65/0.17

y=8645 at 6%

Calculate x

x=17818-8645

x=9173 at 11%

Check

0.11*9173-0.06*8645=490.33

interest earned at 11%=1009.03

interest earned at 6%=518.70

1009.03-518.7=490.33

490.33=490.33

Since this statement is TRUE and neither amount is negative then all is well.

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3 years ago
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