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3 years ago

14

Please help ASAP :) this is really easy ino lol

1 answer:

Zanzabum3 years ago

5 0

Known :

Ratio = Greg : Harry = 1 : 3

Greg's money = £8

Asked :

Harry's money = ...?

Answer :

$\: \ \: \: \: \: \: \: \frac{1}{3} = \frac{greg}{harry} \\ \: \: \: \: \: \: \: \: \frac{1}{3} = \frac{8}{harry} \\ harry = \frac{3 \times 8}{1} \\ harry = 24$

So, Harry gets £24

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

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How to solve 6x - 9 - 2 (1 - x) = x + 9

Likurg_2 [28]

$x = 2.857$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$6x - 9 - 2(1 - x) = x + 9 \\ ⇢ 6x - 9 - 2 + 2x = x + 9 \\ ⇢ 8x - x = 9 + 11 \\ ⇢ 7x = 20 \\ ⇢ x = \frac{20}{7} \\ ⇢ x = 2.857$

${ \bf{ \underbrace{To\:verify:}}}$

$6 \times 2.857 - 9 - 2(1 - 2.857) = 2.857 + 9 \\ ➪ \: 17.142 - 9 - 2 \times( - 1.857) = 11.857 \\➪ \: 8.142 + 3.714 = 11.857 \\➪ \: 11.856 = 11.857 \\ ➪ \: 11.86 = 11.86 \\ ➪ L.H.S.=R. H. S$

Hence verified.

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}$

7 0

2 years ago

Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par

Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that $P(A) = 0.8, P(B) = 0.6$

The probability that at least one part works for one year is 0.9.

This means that: $P(A \cup B) = 0.9$

We also have that:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$0.9 = 0.8+0.6 - P(A \cap B)$

$P(A \cap B) = 0.5$

Calculate the probability that part B works for one year, given that part A works for one year.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625$

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0

3 years ago

Help!giving brainliest and 30 points

eduard

Answer:

D 80

Step-by-step explanation:

step by step

350 +(-350)=0 + 5h = 750 + (-350) =400

5h/5 =400/5=80

h=80

7 0

3 years ago

Which is greater? 12.045 or 12.54

Pavlova-9 [17]

Answer:

12.54

Step-by-step explanation:

5>0

6 0

3 years ago

Read 2 more answers

21 is 30% of what number?

WARRIOR [948]

<u>Answer</u>:

21 is 30% of 70

<u>Explanation</u>:

We know that 100% is the original number.

Equation:

(21/30)*100

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7 * 10

70 ....this is the answer, original number.

5 0

2 years ago

Read 2 more answers