Ask question

Ask question

All categories

3 years ago

14

Please help ASAP :) this is really easy ino lol

1 answer:

Zanzabum3 years ago

5 0

Known :

Ratio = Greg : Harry = 1 : 3

Greg's money = £8

Asked :

Harry's money = ...?

Answer :

$\: \ \: \: \: \: \: \: \frac{1}{3} = \frac{greg}{harry} \\ \: \: \: \: \: \: \: \: \frac{1}{3} = \frac{8}{harry} \\ harry = \frac{3 \times 8}{1} \\ harry = 24$

So, Harry gets £24

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

You might be interested in

Tim Worker estimates his taxable income will be $7,000. He is paid twice a month or 24 times a year. Because Tim has only one so

forsale [732]

$29.30 per period.
According to the tax table for 2017. A taxable income of $7000 will have a tax of $703. 703/24 = 29.29 per paycheck round up my 1 cent to 29.30 to cover the additional 4 cents left over and recieve a 20 cent refund. Source https://www.irs.gov/pub/irs-pdf/i1040tt.pdf

3 0

3 years ago

Read 2 more answers

Translate into an algebraic expression: n−1 increased by 110%

lorasvet [3.4K]

Answer:

Part 1) The algebraic expression is equal to $1.10(n-1)$ or $1.10n-1.10$

Part 2) The algebraic expression is equal to $\frac{1.10}{n}$

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

$1.10(n-1)$

Distributed

$1.10n-1.10$

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

$n^{-1}=\frac{1}{n}$

so

$1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}$

4 0

3 years ago

(a^-3bc^0)^-2/(ab^3c^4)^5

mr Goodwill [35]

6b6
——— (hope this helps)
ac2

5 0

2 years ago

F(x) =5x^2-20x+3 how to find minimum

Leya [2.2K]

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at $x=-\frac{b}{2a}$ . If a is positive, the minimum value of the function is $f(-\frac{b}{2a})$

$f_{min}x=ax^2+bx+c$ occurs at $x=-\frac{b}{2a}$

Find the value of $x=-\frac{b}{2a}$

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

$f(2)=5(2)^2-20(2)+3$

simplify the result.

$f(2)=5(4)-20(2)+3$

$f(2)=20-40+3$

$f(2)=-17$

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!

3 0

3 years ago

Solve for p: a = 2πpw

MaRussiya [10]

Hello there.

<span>Solve for p: a = 2πpw

</span> $\frac{a}{6.283185w
}$

4 0

3 years ago