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Annette [7]
3 years ago
6

Which of these numbers is a prime number: 1, 11, 21, 51?

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

11 and 51

Step-by-step explanation:

1 technically isn't a prime since a prime can only be divided by two things (itself and 1) and 1 can only be divided by 1.

21 can be divided by 1, 3, 7, and 21 so it is not prime.

Hope this helps!

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A crew of meteorologists measured the amount of snowfall in 7 different parts of a mountain town. They each recorded the amount
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Answer:

Your answer would bd B

Step-by-step explanation:

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3 years ago
Is 8d + 4w and 1/2(8d+4w) equivalent
DiKsa [7]

Answer:no

Step-by-step explanation:

Because there is a one half in front of the second one and if the one half wasn’t there,then it would be equivalent bc they are the same number.

8 0
3 years ago
1. Which is an example of an algebraic expression?<br> 04(3 + 8)<br> 018²<br> 03-a<br> 021.4
mars1129 [50]

Answer:

03-a

Step-by-step explanation:

It's an algebraic expression cuz it has an unknown variable (a)

7 0
2 years ago
Read 2 more answers
Maybe can I have some help?
ivann1987 [24]
It’s -5 slope intercept is whatever point the line crosses the y axis
6 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
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