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ozzi
3 years ago
13

How is ordering fractions on a number line similar to andDifferent from ordering whole numbers or on a number line

Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer: Whole numbers are fractions if you add the 1 as the denominator. Fractions on a number line are divided into equal parts but not whole numbers.

Step-by-step explanation: Plz mark as brainleist and leave a thanks

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Which number is divisible by both 2 and 4?<br> A. 1,022<br> B. 1,974<br> C. 2,836<br> D. 2,918
Kobotan [32]
The correct answer is C. 2,836

when 2836 is divided by 2 it equals 1418. when it is divided by 4 it equals 709. 709 is a whole number, therefore it is correct, and can be divided by both 2 and 4.
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Which savings account can a financial institution end?
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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

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