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Mashcka [7]
3 years ago
14

A bag has six balls labeled a,b,c,d.e and f . One ball will be randomly picked, and its letter will be recorded as the outcome.

Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of choosing the letter a or c . If there is more than one element in the set, separate them with commas.
Mathematics
2 answers:
Dvinal [7]3 years ago
8 0
<h3>Sample space = {a,b,c,d,e,f}</h3><h3>Event space = {a,c}</h3>

We simply list all of the letters mentioned as they are the possible outcomes. We can only pick one item from the sample space. The event space is the set of outcomes where we want to happen (picking either an 'a' or 'c').

Tasya [4]3 years ago
6 0

Hey There!!

To this Question, This answer going to had A Explanation to this: Sample space--

A sample space is a set which contains the set of all the possible outcomes or results that could occur while performing an experiment.

i.e. the sample space while flipping a coin is: {H,T}

The sample space while tossing a six-sided die is: {1,2,3,4,5,6}

Here it is given that:

A bag has six balls labeled: A,B,C,D,E,F

One ball will be randomly picked, and its letter will be recorded as the outcome.

This means that the sample space is given by:

Sample space={ A,B,C,D,E,F}

Now, when the event is choosing a letter from D to F.

Then the sample space is:

Sample space= {D,E,F}

Hope It Helped!~ ♡

ItsNobody~ ☆

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Natasha_Volkova [10]

Step-by-step explanation:

Hey there!

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12°+28° = 12x - 7x

40° = 5x

x =  \frac{40}{5}

Therefore, x = 8°

Now,

12x - 28° + 9y - 77 = 180° ( being linear pair)

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96° - 28° + 9y - 77° = 180°

-9 + 9y = 180°

9y = 180° + 9°

y = 189°/9

Therefore, y = 21°

<u>There</u><u>fore</u><u>,</u><u> </u><u>X </u><u>=</u><u> </u><u>8</u><u>°</u><u> </u><u>and</u><u> </u><u>y</u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u><u> </u><u>.</u>

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4 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

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Luba_88 [7]
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The region we're looking for is this sausage-shaped part between the cos and the sin.

The x intercepts are at π/8 for the cosine and π/4 for the sine. The midpoint between them is at (π/8 + π/4)/2 = 3/16π.

The region is point symmetric around the x axis, so the y coordinate of the centroid is 0.

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5 0
3 years ago
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Sloan [31]
<h3>Answer:  4(x - 1)(x^2 + x + 1)</h3>

==================================================

Work Shown:

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4(x^3 - 1)

4(x - 1)(x^2 + x + 1)

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2 years ago
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UNO [17]

Answer:

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Step-by-step explanation:

we have the function

f(x)=\sqrt{-x}

we know that

The radicand must be positive

so

-x \geq 0

Solve for x

Multiply by -1 both sides

x\leq 0

The domain is the interval ------> (-∞,0]

All real numbers less than or equal to zero

The range of the function is the interval -----> [0,∞)

f(x)\geq 0

see the attached figure to better understand the problem

All real numbers greater than or equal to zero

<em><u>Verify each statement</u></em>

case 1) The domain of the graph is all real numbers

The statement is false

Because, the domain is all real numbers less than or equal to zero

case 2) The range of the graph is all real numbers

The statement is false

Because, the range is all real numbers greater than or equal to zero

case 3) The domain of the graph is all real numbers less than or equal to 0

The statement is true

case 4) The range of the graph is all real numbers less than or equal to 0

The statement is false

Because, the range is all real numbers greater than or equal to zero

4 0
3 years ago
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