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lakkis [162]
3 years ago
8

What system of equations is shown on the graph below?

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
4 0

Answer:

The equation of the line passing through the points (-2,0) and (0,-4)

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}

\frac{y - 0}{x  - ( -  2)}  =  \frac{ - 4 - 0}{0 - ( - 2)}  =  \frac{ - 4}{2}  =  - 2

y =  - 2(x + 2) \\ y =  - 2x - 4

2x + y =  - 4

The equation of the line passing through the points (0,-2) and (4,0)

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}  \:

\frac{y - ( - 2)}{x - 0}  =  \frac{0 - ( - 2)}{4 - 0}

\frac{y + 2}{x}  =  \frac{1}{2}

x - 2y = 4

Option B

x minus 2 y = 4 and 2 x + y = negative 4

Alex17521 [72]3 years ago
3 0

Answer:

Your answer is B, y = one-half x minus 2

Step-by-step explanation:

I just took the test!!!!!

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Check the explanation.

Step-by-step explanation:

As the graph of a linear function f passes through the point (-2,-10) and has a slope of 5/2.

As the slop-intercept form is given by:

y = mx+b

where m is the slope and b is the y-intercept.

substituting the values (-2, -10) and m = 5/2 in the slop-intercept form to determine y-intercept.

y = mx+b

-10=\frac{5}{2}\left(-2\right)+b

-\frac{5}{2}\cdot \:2+b=-10

-5+b=-10

-5+b+5=-10+5

b=-5

And the equation of the line in the slope-intercept form will be:

y = mx+b

putting b = -5 and slope = m = 5/2

y = mx+b

y=\frac{5}{2}x+\left(-5\right)

y=\frac{5}{2}x-5

Determining the zero of function.

As we know that the real zero of a function is the x‐intercept(s) of the graph of the function.

so let us determine the value of x (zero of function) by setting y = 0.

0=\frac{5}{2}x-5

\frac{5}{2}x-5=0

\frac{5}{2}x=5

5x=10

x=2

Therefore, the zeros of the function will be:

  • x = 2
3 0
3 years ago
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