7/11 is the answer? I believe so
Formula of square area
a = s²
thus, area of the first square could be written as s₁² and area of the second square could be written as s₂²
First, write an expression in the form of equation system
An expression for "The combined area of two squares is 45 square centimeters" is:
⇒ s₁² + s₂² = 45 <em>(first equation)</em>
An expression for "Each side of one square is twice as long as side of the other" is:
⇒ s₁ = 2s₂ <em>(second equation)</em>
Second, solve the equation system by substitution method.
⇒ We could substitute 2s₂ to s₁ (second equation) in the first equation in order to find the value of s₂
s₁² + s₂² = 45
(2s₂)² + s₂² = 45
(2²)(s₂)² + s₂² = 45
4s₂² + s₂² = 45
5s₂² = 45
s₂² = 45/5
s₂² = 9
s₂² = 3²
s₂ = 3
⇒ Substitute the value of s₂ to the second equation in order to find the value of s₁
s₁ = 2s₂
s₁ = 2(3)
s₁ = 6
The length of each side of the larger square is 6 centimeters
Answer:
180 fb*lb
45 ft*lb
Step-by-step explanation:
We have that the work is equal to:
W = F * d
but when the force is constant and in this case, it is changing.
therefore it would be:
Where a = 0 and b = 30.
F (x) = 0.4 * x
Therefore, we replace and we would be left with:
We integrate and we have:
W = 0.4 / 2 * x ^ 2
W = 0.2 * (x ^ 2) from 0 to 30, we replace:
W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)
W = 180 ft * lb
Now in the second part it is the same, but the integral would be from 0 to 15.
we replace:
W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)
W = 45 ft * lb
Step-by-step explanation:
Since, each group in the range is assigned to only one particular age group, then we can conclude that the group assignment is a one-to-one function.
C, 62
Line segment SQ=180, because it is a straight line
90+28=118
180-118=62
hope this helps:)
