Question

PLEASE ANSWER !!

Answer 1

Answer:

Check the explanation.

Step-by-step explanation:

As the graph of a linear function f passes through the point (-2,-10) and has a slope of 5/2.

As the slop-intercept form is given by:

$y = mx+b$

where m is the slope and b is the y-intercept.

substituting the values (-2, -10) and m = 5/2 in the slop-intercept form to determine y-intercept.

$y = mx+b$

$-10=\frac{5}{2}\left(-2\right)+b$

$-\frac{5}{2}\cdot \:2+b=-10$

$-5+b=-10$

$-5+b+5=-10+5$

$b=-5$

And the equation of the line in the slope-intercept form will be:

$y = mx+b$

putting b = -5 and slope = m = 5/2

$y = mx+b$

$y=\frac{5}{2}x+\left(-5\right)$

$y=\frac{5}{2}x-5$

Determining the zero of function.

As we know that the real zero of a function is the x‐intercept(s) of the graph of the function.

so let us determine the value of x (zero of function) by setting y = 0.

$0=\frac{5}{2}x-5$

$\frac{5}{2}x-5=0$

$\frac{5}{2}x=5$

$5x=10$

$x=2$

Therefore, the zeros of the function will be:

• x = 2