The mistake is in step 3:
I: −2m =−12 − 2n
II: 2m = 8 + 8n
the student set both right sides of the equations equal (−12 − 2n = 8 + 8n), but the left sides aren't equal: first equation has -2m, second has +2m so the signs of one of the equations must be inverted first
answer is (-7,2)
y = -x -5
y= x+9
Both equations have y on the left hand side
So we equate both equations
We replace -x-5 for y in the second equation
-x -5 = x+9
Subtract x on both sides
-2x -5 = 9
Now add 5 on both sides
-2x = 14
Divide by -2 from both sides
x = -7
Now plug in -7 for x in the first equation
y = -x -5
y = -(-7) -5= 7-5 = 2
So answer is (-7,2)
Answer:
6 = 4 mins
Step-by-step explanation:
you have to take 200 and 50 and divide them
200 divided by 50 =4 and you have to tack mins to the end of it
id_k how many class rooms for number 5
and 7 i dk how many weeks there are therefore i cant solve them
Answer:
Hello a value is missing in your question below is the value
samples of n = 10
answer : 24.63 < μ < 25.370
Step-by-step explanation:
Given :
Sample size = n = 10
Z∝/2 = Z0.0256 = 1.95
next calculate for margin of error
E = Z∝/2 * ( 0.6 / / 
)
= 0.370
therefore at 94.87% confidence interval the estimated population mean is
x - 0.370 < μ < x + 0.370
25 - 0.370 < μ < 25 + 0.370
24.63 < μ < 25.370
Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
