Answer:
Step-by-step explanation:
Given that,
y' = 17y ( 1-y^7)
Let y=1
Then, y' = 0 for all t
Then show that it is the only stable equilibrium point so that as y→1, t→∞ with any initial value.
So, the graph solution will be
y(0) = 1 and this will be an horizontal line
If, y(0) > 1 then, y' < 0 by inspecting the first equation, so the graph is has decreasing solution.
Likewise, if y(0) < 1 then, y' > 0 and the graph is increasing.
So no matter the initial condition, graph of the solution will be asymptotic to the horizontal line above.
This make the limit be 1.
This shows that x = 1 is a stable equilibrium.
Y = x² to: y = - 2 ( x - 2 )² + 2
Answer:
D ) reflect across the x-axis, translate 2 units to the right, translate up 2 units, stretch by the factor of 2
Answer:
It is b.
Step-by-step explanation:
When x is negative x^5 will also be negative.
f(x) = x^5 - 3x^3 + 2x + 4
As x --> -∞ x^5 will be the main factor for f(x) ---> -∞ .
Similarly x^5 will have the greatest influence when x ---> ∞, so f(x) ---> ∞.
Answer:
150
Step-by-step explanation:
