The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
Answer:
The coordinates of B are (-2 , 9)
Step-by-step explanation:
A (8, 4)
M (3 , -1)
To calculate a midpoint you have to add the corresponding coordinates of each point and divide them by 2
(Ax + Bx) / 2 = Mx
(8 + Bx) / 2 = 3
8 + Bx = 3 * 2
Bx = 6 - 8
Bx = -2
(Ay + By) / 2 = My
( -1 + By) / 2 = 4
-1 + By = 4 * 2
By = 8 + 1
By = 9
The coordinates of B are (-2 , 9)
You eliminate or ‘take away’ the answers that you know or think that r wrong. The last answer that’s left is your answer.
40 ways. 6!/3!(6-3)! =120. We are only trying to find 3 ways. 120 is the total, 120/30 =40. So 40 is the answer.
