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sergiy2304 [10]
3 years ago
11

12n^3 + 16n^3 can someone please help me with this?

Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0

Answer:

4n^{3} (3n^{2} + 4)

Step-by-step explanation:

Assuming the problem is asking you to factor out the formula, it can be done easily by finding a common number with the two givens.

4 goes into both 12 and 16 evenly, so we will use this to factor. But that's not all, we have the n-variable to worry about.

Look at the n-variable exponents in the problem, take the highest power that can go be subtracted from both and use that. We have a n^{5} and n^{3}. Since 5 can't go into 3, we must use 3 to factor.

Our factoring variable will therefore be 4n^{3}. Now, use this to simply divide and get the answer:

( 12n^{5} + 16n^{3} ) / 4n^{3}  = 4n^{3}(3n^{2} + 4)

So how did we get this? For the whole numbers, we have to divide: (12/4, 16/4). Next, we have to minus the exponents since we are dividing.

When dividing the 12 and 4, minus the n^{5} and n^{3} to get n^{2}. Get rid of the n^{3} term for the 16 and leave the 4. And there's your answer!

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