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pshichka [43]
3 years ago
9

Lisa sold her old bike for $140 less than she paid for it. She sold the bike for $85. Write and solve and equation to find how m

uch Lisa paid for her bike.
Mathematics
1 answer:
rodikova [14]3 years ago
4 0

Answer:

Equation=$140+$85=$225

Step-by-step explanation:

If she sold her bike for $140 less than she paid for it, and she sold it for $85, you add 140 to 85 to get out much she paid for. To check your answer do 225-140=85.

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answer
</span><span>A:–5cd </span>
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3 years ago
Which expression is equivalent to (x – 1)7?
aleksley [76]
Hello!

The answer is B

Hope this helps!
6 0
3 years ago
(6x+3) (4x-5) (simp) I try to do this one and got the answer 24x^2-18x-15 but I was told it was wrong
Gemiola [76]

Answer:

(6x+3) (4x-5) = 24x^2 -30x +12x -15 = 24x^2 -18x -15

I get the same answer.  I guess we're both wrong?

Or do they want it reduced to:

8x^2 -6x -5


Step-by-step explanation:


8 0
3 years ago
Interest = $45.58, time = 1 year, rate = 2.25%. Find the principal. Round to the nearest hundredth place
Murrr4er [49]

Answer:

<em>$2,025.78 </em>

Step-by-step explanation:

I = Prt ⇒ P = \frac{I}{rt}

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8 0
2 years ago
The fuel efficiency (mpg rating) for cars has been increasing steadily since 1980. The formula for a car's fuel efficiency for a
Lisa [10]

Answer:

a) In the interval of [1980,1983].

b) In the interval of [1991, 1996].

Step-by-step explanation:

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The fuel efficiency, for the cars, in x years after 1980, is given by:

E(x) = 0.36x + 15.9

15.9 is the fuel efficiency in 1980.

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From 1980 to:

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0.36x < 1.1

x < \frac{1.1}{0.36}

x < 3.06

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In the interval of [1980,1983].

b. In what years was the average fuel efficiency for cars more than 20 mpg (in interval form)?

From x until 1996.

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0.36x > 4.1

x > \frac{4.1}{0.36}

x > 11.38

11.38 = 1980 + 11 = 1991. So

In the interval of [1991, 1996].

4 0
3 years ago
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