The distance between point J and line KL would be the line perpendicular to the line, which is line JM.
The answer would be B.
[ - 6 * x^2 * y^8 + 12* x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =
[-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =
- xy^6 + 2y - 6
Answer: - xy^6 + 2y - 6
First distribute 3 to (x-4). that gives you 3x-12. Now your equation is x-2=3x-12. Now you subtract x from 3x. now you're equation is -2=2x-12. then add 12 to the left. You're final answer is 10.
