Answer:
H0 : σ = 0.5
H0 : σ < 0.5
Step-by-step explanation:
From the scenario described above, the company wants to see conclusive evidence that the population standard deviation of sheath thickness is less than .05 mm ; THIS SIMPLY means ; REJECTION OF the NULL HYPOTHESIS. This is because once there is a significant or conclusive evidence in hypothesis testing, then we reject the null and support the claim of the alternative hypothesis.
Hence, the alternative hypothesis is ; population standard deviation of sheath Thickness is less than 0.5.
H1 : σ < 0.5 ;
Therefore, our null will be ;
H0 : σ = 0.5
To find the answer,
Multiply the term with 4 then subtract with 3
Lets take the term as 'n'
Formula = 4n-3
Value of 8th term = (4*8)-3
= 32-3
= 29
The value of 8th term is 29
Hmm idk.... I need like more info for this please so I can help you thank you byeeeee
Since it's so nicely grouped, we can work with it! For the equation to equal 0, x=0, 3, or -1 (since x-3 and x+1 equal 0 when plugged in with 3 and -1 respectively). All we have to do is plug in numbers before, between, and after these numbers and apply it to the rest of them. Since -1 is the smallest number of the group, we can plug in a number below that (for this example, -5) and plug it in to get -8*-5*-4= something negative since it contains an odd number of negative numbers. Therefore, anything less than 1 is negative. For between -1 and 0, we get x=-0.5 equals -0.5*-3.5*0.5=something positive (since it has an even amount of negative numbers), proving that everything between -1 and 0 here is positive. For something between 0 and 3, we can plug 1 in to get 1*-2*2= something negative. Do you see a pattern here? It's negative, then positive, etc.. Therefore, if the number is greater than 3 it is positive. Reviewing a bit, we can see that (-inf, -1) is negative as well as (0,3), making the interval notation (-inf, -1) U (0, 3) since when you plug -1, 0, and 3 in it is 0, not less than 0!
Answer:
-8/5
Step-by-step explanation:
y values minus each other over x values minus each other
