Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.
We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.
According to Pythagoras
.... (1)
Put z=1 and y=2, to find the value of x.
Taking square root both sides.
Differentiate equation (1) with respect to t.
Divide both sides by 2.
Put , y=2, in the above equation.
Divide both sides by 2.
Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Answer:
72 m
Step-by-step explanation:
When X=0, the function would be:
<span>f(x) = 4x^3 -20x2 + 24x
0= </span><span>4x^3 -20x2 + 24x ----->divide all by x
</span>x(4x^2 -20x + 24) =0 ------> split -20x into -12x and -8x
x(4x^2 -12x -8x + 24)
x{4x(x-3) - 8(x -3}
x(4x-8) (x-3)
x1= 0
x2= 8/4= 2
x3= 3
E+(e-24)=126
2e-24=126
2e=150
e=75
So (s)he recieved 75 and 75-24=51 emails on those days.
Answer:
3x-4y-6x+28y
-3x-6x-4y+28y
-9x+24y
Step-by-step explanation: