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Stolb23 [73]
3 years ago
12

Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (

c squared minus 9) EndFraction?
StartFraction c + 3 Over c squared minus 4 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction


StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction 3 (c squared minus 9) Over c + 2 EndFraction


StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction 3 (c squared minus 9) Over c + 2 EndFraction


StartFraction c squared minus 4 Over c + 3 EndFraction times StartFraction c + 2 Over 3 (c squared minus 9) EndFraction
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Firdavs [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Given:

\dfrac{c^2-4}{c+3}\div  \dfrac{c+2}{3(c^2-9)}

Changing the division to multiplication by taking the reciprocal of the second fraction.

\dfrac{c^2-4}{c+3}X  \dfrac{3(c^2-9)}{c+2}

<u>The correct option is C</u>

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A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

6 0
3 years ago
What is 4,7,12,19,28 in quadratic form
Naddik [55]
Asked and answered elsewhere.
brainly.com/question/9247314

You obviously don't mind using "technology" (Brainly) to answer these questions. A graphing calculator can do quadratic regression on the sequence and tell you its formula.

If you want to do it by hand, you can write the equation
.. y = ax^2 +bx +c
and substitute three of the given points. Then solve the resulting three linear equations for a, b, and c.
.. 4 = a +b +c
.. 7 = 4a +2b +c
.. 12 = 9a +3b +c

Subtracting the first equation from the other two reduces this to
.. 3 = 3a +b
.. 8 = 8a +2b
The latter can be divided by 2, so reduces to
.. 4 = 4a +b
Subtracting the first of the reduced equations from this, you have
.. 1 = a
so
.. 3 = 3*1 +b
.. 0 = b
and
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And your equation is
.. y = x^2 +3 . . . . . . as shown previously

7 0
3 years ago
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Musya8 [376]

Answer:

angle Y = 90 degrees

Step-by-step explanation:

Since it is stated that angle x forms a straight line with the 50 and 50 degree angles, and that angle x is vertical to angle y, we can do 40+50+y=180 to find angle Y.

8 0
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For the function f(x) = -3x + 2, what is the local
jolli1 [7]
The answer would be

F(x)=x^2-8x
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Tresset [83]

Given:

Replace f(x) by f(x - h).

To find:

The effect on the graph of replacing f(x) by f(x - h).

Solution:

Horizontal shift is defined as:

If the graph f(x) shifts h units left, then f(x+h).

If the graph f(x) shifts h units right, then f(x-h).

Where, h is a constant that represents the horizontal shift.

In the given problem f(x) is replaced by f(x - h) and we need to find the effect on the graph.

Here, we have x-h in place of x.

Therefore, the graph of f(x) shifts h units right to get the graph of f(x-h).

4 0
3 years ago
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