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3 years ago

Dianne measured the thickness of 1000 sheets of paper as 264mm. How thick is the sheet? Please hurry anyone!!!!!

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

0.264 mm

Step-by-step explanation:

Number of sheets = 1000

Thickness of entire sheet = 264 mm

The thickness of the sheet is :

Thickness of entire sheet / number of sheets

264 mm / 1000

= 0.264 mm

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At Otto’s egg farm, Otto has found that when he charges $0.05 per egg, he sell so many eggs that he cannot keep up with the dema

PilotLPTM [1.2K]

Answer:

a) P(c) = xc² + yc + z, and P(.15) = $124, P(.05) = 0, P(.17) = 0. Thus:

(#1) .0225x + .15y + z = 124

(#2) .0025x + .05y + z = 0

(#3) .0289x + .17y + z = 0

Subtracting #2 from #3: (#4) .0264x + .12y = 0

Subtracting #2 from #3: (#5) .02x + .1y = 124

Subtracting 1.2×#5 from #4: .0024x = -148.8 → x= -62000

Using this value of x in #5: -1240 + .1y = 124 → y = 13640

Using x and y in #1: -1395 + 2046 + z = 124 → z = -527

P(c) = -62000c² + 13640c - 527

b) To find the maximum of P(c), find a such that P'(a) = 0

-124000c + 13640 = 0

c = .11

At this price, his profit would be $223.20

3 0

3 years ago

NEED HELP PLEASE BEGGING PLEASE!!!!

Sliva [168]

Answer:

-54

Step-by-step explanation:

$8(-9) - 6(-3)\\$

Multiply 8 by -9 and 6 by -3

$-72 - (-18)$

Subtract $Value = -54$

Hope this helps

plz mark brainliest

6 0

3 years ago

The sum of an integer and 3 times the next consecutive integer is -21. Find the value of the greater integer.

Anni [7]

Answer: -5

Step-by-step explanation:

i=integer

i+3(i+1)=-21

i+3i+3=-21

4i+3=-21

4i=-24

i=-6

i+1=-6+1=-5

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1 year ago

029494737+8489949494

skelet666 [1.2K]

Answer:

8519444231

I hope this helps!

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3 years ago

Read 2 more answers

Jack recieved $600 for his birthday. If he saves it in a bank account with 8% interest compounded yearly, how much money will he

Gwar [14]

so 21 - 13, the money will be invested for 8 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$600\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\to &1\\ t=years\to &8 \end{cases} \\\\\\ A=600\left(1+\frac{0.08}{1}\right)^{1\cdot 8}\implies A=600(1.08)^8\implies A\approx 1110.558126$

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3 years ago