I think it eould be 17 feet. 5 plus 8 plus 4 is 17.
Answer:
The probability that all the five flights are delayed is 0.2073.
Step-by-step explanation:
Let <em>X</em> = number of domestic flights delayed at JFK airport.
The probability of a domestic flight being delayed at the JFK airport is, P (X) = <em>p</em> = 0.27.
A random sample of <em>n</em> = 5 flights are selected at JFK airport.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The probability mass function of <em>X</em> is:
![P(X=x)={5\choose x}0.27^{x}(1-0.27)^{5-x};\ x=0,1,2...](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%7B5%5Cchoose%20x%7D0.27%5E%7Bx%7D%281-0.27%29%5E%7B5-x%7D%3B%5C%20x%3D0%2C1%2C2...)
Compute the probability that all the five flights are delayed as follows:
![P(X=5)={5\choose 5}0.27^{5}(1-0.27)^{5-5}=1\times 1\times 0.207307=0.2073](https://tex.z-dn.net/?f=P%28X%3D5%29%3D%7B5%5Cchoose%205%7D0.27%5E%7B5%7D%281-0.27%29%5E%7B5-5%7D%3D1%5Ctimes%201%5Ctimes%200.207307%3D0.2073)
Thus, the probability that all the five flights are delayed is 0.2073.
Answer:
1. 36
2. 90
3. 9
4. 6
Step-by-step explanation: