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lorasvet [3.4K]
3 years ago
7

Kate paid $27 for a dress that was on sale for 10% off. What was the original price of this dress?

Mathematics
2 answers:
Luba_88 [7]3 years ago
8 0
The best way to go about this questions is to write out a formula in which x represents the original price of the dress: x*0.90=27. To see where the 0.90 came from, if Kate's dress was 10% off, she must have paid 90% of the original price (100%-10%=90%). Then, to convert a percentage to a decimal, move the decimal point twice to the left so 90% becomes 0.90. Then, our formula essentially means that 90% of some number (x) is equal to 27. To solve for x, divide both sides of the formula by 0.90 to get x=$30 which is the final answer.

I hope this helps.
zlopas [31]3 years ago
5 0

Answer:

$30

Step-by-step explanation:

The dress was 10% off, so 100% - 10% = 90%

90% is what percent she paid for the dress.

$27 is 90% the original price.

27/x = 90/100

90x = 2700

x = 30

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For the cost function c equals 0.1 q squared plus 2.1 q plus 8​, how fast does c change with respect to q when q equals 11​? Det
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Rate of change of c with respect to q is 4.3

Percentage rate of change c with respect to q is  9.95%

Step-by-step explanation:

Cost function is given as,  c=0.1\:q^{2}+2.1\:q+8

Given that c changes with respect to q that is, \dfrac{dc}{dq}. So differentiating given function,  

\dfrac{dc}{dq}=\dfrac{d}{dq}\left (0.1\:q^{2}+2.1\:q+8 \right)

Applying sum rule of derivative,

\dfrac{dc}{dq}=\dfrac{d}{dq}\left(0.1\:q^{2}\right)+\dfrac{d}{dq}\left(2.1\:q\right)+\dfrac{d}{dq}\left(8\right)

Applying power rule and constant rule of derivative,

\dfrac{dc}{dt}=0.1\left(2\:q^{2-1}\right)+2.1\left(1\right)+0

\dfrac{dc}{dt}=0.1\left(2\:q\right)+2.1

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Substituting the value of q=11,

\dfrac{dc}{dt}=0.2\left(11\right)+21.

\dfrac{dc}{dt}=2.2+2.1

\dfrac{dc}{dt}=4.3

Rate of change of c with respect to q is 4.3

Formula for percentage rate of change is given as,  

Percentage\:rate\:of\:change=\dfrac{Q'\left(x\right)}{Q\left(x\right)}\times 100

Rewriting in terms of cost C,

Percentage\:rate\:of\:change=\dfrac{C'\left(q\right)}{C\left(q\right)}\times 100

Calculating value of C\left(q \right)

C\left(q\right)=0.1\:q^{2}+2.1\:q+8

Substituting the value of q=11,

C\left(q\right)=0.1\left(11\right)^{2}+2.1\left(11\right)+8

C\left(q\right)=0.1\left(121\right)+23.1+8

C\left(q\right)=12.1+23.1+8

C\left(q\right)=43.2

Now using the formula for percentage,  

Percentage\:rate\:of\:change=\dfrac{4.3}{43.2}\times 100

Percentage\:rate\:of\:change=0.0995\times 100

Percentage\:rate\:of\:change=9.95%

Percentage rate of change of c with respect to q is 9.95%

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