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lorasvet [3.4K]
4 years ago
11

A fence on a hill uses vertical posts L and M to hold parallel rails N and P. If m∠1 = 6x and m∠12 = 4x, then what is the measur

e of ∠5?

Mathematics
2 answers:
goldenfox [79]4 years ago
5 0

Answer;

D: 108 degrees



amm18124 years ago
3 0

Answer:

Measure of ∠5 is 108°

Step-by-step explanation:

Given m∠1 = 6x and m∠12 = 4x, we have to find the measure of ∠5.

As ∠1 and ∠5 are alternate exterior angle hence equal i.e ∠1=∠5

Also, ∠5 and ∠12 are co-interior angles ∴these are supplementary

⇒ m∠5+m∠12=180°

⇒ 6x+4x=180°

⇒ 10x = 180°  ⇒  x=18

∴ m∠5 = 6x = 6(18) = 108°

Hence, measure of ∠5 is 108°

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Your friends shuffle the cards and then deal them. Select probability of getting a red card. Select probability of getting a spa
sladkih [1.3K]

Answer:

1/2 ; 1/4

Step-by-step explanation:

Number of cards in a deck = 52

Number of red cards = 26

Number of spades = 13

Probability of event A :

P(A) = required outcome / Total possible outcomes

P( red card) = number of red cards / total cards in deck

P(red card) = 26 / 52 = 1/2

P(spade) = number of spades / total cards in deck

P(red card) = 13 / 52 = 1 / 4

7 0
3 years ago
A plane is at Manchester, which is 170km north of Worcester. The plane flies in a straight line for 230km and lands in Cambridge
german
The plane has to go back north
7 0
3 years ago
How do I solve this ?? And what is the answer ??
Murljashka [212]
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6 0
3 years ago
The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units?
valentinak56 [21]
24+24+11+11=60?
48+22=60?
60=60?
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8 0
4 years ago
The point (2, 1) is a solution to which of the following systems of equations?
Snezhnost [94]

\huge\boxed{\left \{ {{x+y=3} \atop {3x-y=5}} \right.}

We can solve this problem by testing the solution against each system of equations. We'll do this by substituting the point into each equation for each system.

<h2>System 1 - \Large\textbf{X}</h2>

\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}2x+y&=5\\2(2)+1&=5\\4+1&=5\\5&=5\\&\checkmark\end{aligned}&\begin{aligned}-2x+y&=2\\-2(2)+1&=2\\-4+1&=2\\-3&=2\\&\text{X}\end{aligned}\end{array}

<h2>System 2 - \Large\textbf{X}</h2>

\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}-2x-y&=-5\\-2(2)-1&=-5\\-4-1&=-5\\-5&=-5\\&\checkmark\end{aligned}&\begin{aligned}2x-y&=2\\2(2)-1&=2\\4-1&=2\\3&=2\\&\text{X}\end{aligned}\end{array}

<h2>System 3 - \Large\textbf{X}</h2>

\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}-x+y&=3\\-2+1&=3\\-1&=3\\&\text{X}\end{aligned}&\begin{aligned}-3x+y&=-5\\-3(2)+1&=-5\\-6+1&=-5\\-5&=-5\\&\checkmark\end{aligned}\end{array}

<h2>System 4 - \Large\checkmark</h2>

\begin{array}{c|c}\textbf{First Equation}&\textbf{Second Equation}\\\cline{1-2}\begin{aligned}x+y&=3\\2+1&=3\\3&=3\\&\checkmark\end{aligned}&\begin{aligned}3x-y&=5\\3(2)-1&=5\\6-1&=5\\5&=5\\&\checkmark\end{aligned}\end{array}

Since both equations in the final system are true when solved with (2, 1), the answer is the last system.

3 0
3 years ago
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