The Jacobian for this transformation is
with determinant 
, hence the area element becomes
Then the integral becomes
where 
is the unit circle,
so that
Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.
Then
We can't eliminate as is so we have to change something up there in the equations to get either the x values the same number but opposite signs, or the y values the same number but opposite signs. I chose to change the y values to the same number but different signs. In the first equation y is -3y and in the second one, y is -8y. The LCM of both of those numbers is 24, so we will multiply the first equation by an 8 (8*3=24) and the second equation by 3 (3*8=24) but since they are both negative right now, one of those multiplications has to involve a negative because - * - = +. Set it up like this:
8(-10x - 3y = -18)
-3(-7x - 8y = 11)
Multiply both of those all the way through to get new equations:
-80x - 24y = -144
21x +24y = -33
Now the y's cancel each other out leaving only the x's:
-59x = -177 and x = 3. Now plug that 3 into either one of the original equations to find the y value. Either equation will work; you'll get the same answer using either one. Promise. -7(3) - 8y = 11 gives a y value of -4. so your solution is (3, -4) or B above.
Remember, if you add negative four, you're really subtracting four, or if you take away negative four, you're really adding four.
-n+(-4)-(-4n)+6
-n-4+4n+6 simplify
{-n+4n are like terms, so combine them. -n+4n is exactly the same as 4n-n, so flip them around if it helps. Just remember to keep the sign with the right number. Same thing with -4+6.}
Answer:
3n+2
First of all u spelled which wrong second there are infinity prime numbers third some prime numbers are 2,3,5,7,11,13,17,19,23,and 29
