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4 years ago

Evaluate the dot product of (6,-3) and (8,5).

1 answer:

6 0

Not sure what you mean by dot product, maybe explain and I can help better but the two make an equation of y= 4/1 x + -27, that is the equation of the line.

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In order to budget successfuly, one must make a. a lot of money. c. expensive purchases. b. healthy financial choices. d. sure t

julsineya [31]

B. healthy financial choices

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4 years ago

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Find the value of z A.110 B.141 C.80 D.100

gladu [14]

Answer:

<h2>Option A 110degree is the answer </h2>

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3 years ago

Find the area of the kite p=17 q =15.3

Semenov [28]

Answer:

$\large\boxed{A=130.05}$

Step-by-step explanation:

The formula of an area of a kite:

$A=\dfrac{pq}{2}$

p, q - diagonals

We have p = 17 and q = 15.3. Substitute:

$A=\dfrac{(17)(15.3)}{2}=\dfrac{260.1}{2}=130.05$

3 0

3 years ago

I need the answer for number 3, I just need to know what the acceleration is

Lerok [7]

Acceleration = 9.8 m/s
OR you might use 10m/s at your level (i'm not sure which)

7 0

3 years ago

For a test of population proportion H0: p = 0.50, the z test statistic equals 1.05. Use 3 decimal places. (a) What is the p-valu

sergiy2304 [10]

Answer:

(a) The p-value of the test statistic is 0.147.

(b) The p-value of the test statistic is 0.294.

(d) None of the p-values give strong evidence against the null hypothesis.

Step-by-step explanation:

The p-value is well defined as the probability,[under the null hypothesis (H₀)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

We reject a hypothesis if the p-value of a statistic is lower than the level of significance α.

The null hypothesis for the test of population proportion is defined as:

H₀: p = 0.50

The value of z-test statistic is,

z = 1.05

(a)

The alternate hypothesis is defined as:

Hₐ: p > 0.50

Compute the p-value of the test statistic as follows:

$p-value=P(Z>1.05)\\=1-P(Z$

*Use a z-table for the probability value.

Thus, the p-value of the test statistic is 0.147.

(b)

The alternate hypothesis is defined as:

Hₐ: p ≠ 0.50

Compute the p-value of the test statistic as follows:

$p-value=2\times P(Z>1.05)\\=2\times 0.1469\\=0.2938\\\approx 0.294$

*Use a z-table for the probability value.

Thus, the p-value of the test statistic is 0.294.

(c)

The alternate hypothesis is defined as:

Hₐ: p < 0.50

Compute the p-value of the test statistic as follows:

$p-value= P(Z1.05)=1- 0.1469\\=0.8531$

*Use a z-table for the probability value.

Thus, the p-value of the test statistic is 0.8531.

(d)

The decision rule of the test is:

If the p-value of the test is less than the significance level α, then the null hypothesis is rejected at α% level of significance.

And if the p-value of the test is more than the significance level α, then the null hypothesis is failed to be rejected.

The most commonly used level of significance are:

α = 0.01, 0.05 and 0.10

The p-value for all the three alternate hypothesis are:

p-values = 0.147, 0.294 and 0.8531.

All the p-values are quite large compared to the α values.

Thus, none of the p-values give strong evidence against the null hypothesis.

The null hypothesis was failed to be rejected.

5 0

3 years ago