Try multiplying it
we know that 8 times 10=80 so multiply 80 by 2, then 3 then 4 untill you get close to that number so
80 times 2=160
80 times 3=240
80 times 4=320
this is over so it is more than 30 8's but less than 40 8's
so start from 320
subtract 293 from 320
320-293=27
divide 27 by 8
27/8=3 and 3/8
add that to 30
33 and 3/8 8's will fit
the teacher probably wants how many whole 8's can fit so get rid of the 3/8 and just put 33 8's
The hardest part of this would be finding the length of that arc. Though, since it's a quarter circle, it makes our job a whole lot easier.
The circumference of a circle is 2πr, therefore, a quarter circumference of a circle would be (2<span>πr) / 4.
</span>
Therefore, the length of that arc would be (2 * 3.14<span> * 8) / 4 = 12.56
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With this figure, we can just add up the rest of the perimeter.
12.56 + 8 (circle radius) + 10 + 10 (two rectangle heights) + 17 (rectangle length) + 9 (rectangle length minus radius, for the top-right part of the rectangle), giving us an answer of 66.56cm
Answer:
<h3>
Given equation</h3>
<h3>Solve it for y</h3>
1. Cross - multiply:
2. Open parenthesis:
3. Collect like terms:
4. Simplify:
5. Divide both sides by 42:
Matching answer choice is B
Answer:
Its D
Step-by-step explanation:
I solved with addition elimination, and matrices elimination and received the same answer. (0,0,-3) I hope that helps.
