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2 years ago

What Is the answer to -0.35 times -1 3/7

Mathematics

1 answer:

Oliga [24]2 years ago

6 0

Answer:

0.5

Step-by-step explanation:

-0.35 x 1.43=0.5

3/7= .43

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To improve his basketball skills, Troy decides to practice six times as many free throws and four times as many jump shots every

noname [10]

The answer is B. 6f+4j

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3 years ago

Read 2 more answers

X^3+x²-36 Find all real zeros.

Harman [31]

Answer: x=3

Step-by-step explanation:

To find the zeros, you want to first factor the expression.

x³+x²-36

(x-3)(x²+4x+12)

Now that we have found the factors, we set each to 0.

x-3=0

x=3

Since x²+4x+12 cannot be factored, we can forget about this part.

Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.

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3 years ago

Please help :( Im desperate

ki77a [65]

Answer:

(2,4)

Step-by-step explanation:

When graphed the lines intersect at point (2,4) which is the solution.

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2 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

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3 years ago

In poker, a flush is when all five cards are the same suite, what is the probability the first card is a club?

solong [7]

There are 13 clubs and 52 cards for a probability of 13/52= 1/4 for the first card being a club...

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3 years ago