Since m is the midpoint of gh, both of the x, y coordinates of m should be the average of that of g and h. Let h=(x,y). 5=(1+x)/2, x=2*5-1=9; 3=(-5+y)/2, y=2*3-(-5)=11. So h(9,11).
Answer:
157 cm^2
Step-by-step explanation:
1) find the radius
radius = side of the square /2 = 10 /2 = 5 cm
2) notice that four semicircles are equals to two circles
3) find the area of the shaded region
A = radius^2 x pi x 2 = 5^2 x pi x 2 = 157 cm^2 (round the nearest whole number)
It would be Y=-4x+10. Please mark me brainliest. It’s fine if you don’t want to tho.
Answer: C
Step-by-step explanation:
V=4
/3πr3
Answer:1700
Step-by-step explanation: