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marissa [1.9K]
3 years ago
8

The given amount of annual interest is earned from a total of $13,000 invested in two funds paying simple interest. Write and so

lve a system of equations to find the amount invested at each given rate.
Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

because it just is this is not the actual answer

Step-by-step explanation:

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Is 19 2/9 a integer​
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In a survey of 150 students at Kennedy Middle School, 48% said
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660 people

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Identify the median and IQR of the data set below.20222426283032Your answerWhich dota
Dennis_Churaev [7]

We are given a boxplot that contains some data. We will use the information below to analyze the given question.

STEP 1: Median

From the image above, we can see that the median represents the line drawn inside the box

This gives;

\text{Median}=24

STEP 2: Interquartile range

The interquartile range is the difference between the third quartile and the first quartile.

\begin{gathered} q_3=28 \\ q_1=22 \\ \text{IQR}=28-22 \\ \text{IQR}=6 \end{gathered}

4 0
1 year ago
Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

8 0
3 years ago
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