Answer:
The answer is 2nd point
Step-by-step explanation:
In this question, inverse of f(x) is equals to g(x). First, you must know how to find the inverse of f(x). In order to find the g(x), you must let f(x) = y and make x thd subject :
1.
Let y = (10x+9)/8
y = (10x+9)/8
8y = 10x + 9
8y - 9 = 10x
(8y-9)/10 = x
x = (8y-9)/10
g(x) = (8x-9)/10 (Remember to convert y back to x)
2.
Let y = x - 9
y = x - 9
y + 9 = x
x = y + 9
g(x) = x + 3
Next, by looking in no.1, the inverse of f(x) is wrong and in no.2, it shows the correct form of inverse. So only 2 is an inverse function
Answer: 8.525
Step-by-step explanation:
Well, first you need to decide what place you want to round it TO.
Example: Round it to the nearest hundredth:
The next larger hundredth is 186.29 .
The next smaller hundredth is 186.28 .
Now look at it.
186.282 is closer to 186.28 than it is to 186.29 .
So the nearest hundredth is 186.28 .
-- When 186.282 is rounded to the nearest hundredth, it becomes 186.28 .
Similarly . . .
-- When 186.282 is rounded to the nearest tenth, it becomes 186.3 .
-- When 186.282 is rounded to the nearest whole number, it becomes 186 .
-- When 186.282 is rounded to the nearest ten, it becomes 190 .
-- When 186.282 is rounded to the nearest hundred, it becomes 200 .
-- When 186.282 is rounded to the nearest thousand or anything larger,
it becomes zero.
I'm curious . . . where did this number come from ?
It happens to be one thousandth of the speed of light, in miles per hour.
Did it come up in science class, or did a science geek use it for
one of the problems in math ?
Interest calculator for a $600 investment. How much will my investment of 600 dollars be worth in the future? Just a small amount saved every day, week, or month can add up to a large amount over time. In this calculator, the interest is compounded annually.
Answer:
A
Step-by-step explanation:
First, put this equation in slope intercept form.
Where m is the slope and b is the y intercept.
Since it's greater than, the solution set is above the line, effectively eliminating graph D.
Now we should graph it.
We can see that the point 
is on the graph, and only Graph A has that point. Therefore, Graph A is the correct graph.
