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bezimeni [28]
3 years ago
15

A round-robin tennis tournament consists of each player playing every other player exactly once. How many matches will be held d

uring an 8-person round-robin tennis tournament
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

The answer is "28"

Step-by-step explanation:

Given value:

total person =8

using formula:

\to \frac{n(n-1)}{2}

\to \frac{8(8-1)}{2}\\\\\to \frac{8(7)}{2}\\\\\to \frac{56}{2}\\\\\to 28

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Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

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Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990  = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

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Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993  = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

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Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

6 0
3 years ago
What is a num between 234,457.7 and 234,457.8.
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6 0
3 years ago
A line passes through the point (0,6) and is parallel to the line with the equation y =
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Answer:

First option is the correct choice.

Step-by-step explanation:

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Best Regards!

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<span>What is 1990 divided by 24?
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