Question

A round-robin tennis tournament consists of each player playing every other player exactly once. How many matches will be held during an 8-person round-robin tennis tournament

Answer 1

Answer:

The answer is "28"

Step-by-step explanation:

Given value:

total person =8

using formula:

$\to \frac{n(n-1)}{2}$

$\to \frac{8(8-1)}{2}\\\\\to \frac{8(7)}{2}\\\\\to \frac{56}{2}\\\\\to 28$