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4 years ago

Which triangles are congruent by ASA?

Mathematics

2 answers:

olganol [36]4 years ago

3 0

Side BC is congruent to side DC. (That's what the hash marks mean.) Angle C is congruent with itself, and the right angles at B and D are all congruent.

Thus, you want to choose triangle names that show BC congruent to DC. The appropriate selection is the second one ...
∆ADC ≅ ∆EBC

Vlad1618 [11]4 years ago

3 0

Angle C is congruent to angle C. (A pair of angles)
Side CB is congruent to side CD. (A pair of sides)
Angle CBE is congruent to angle CDE. (A pair of angles)

By ASA, triangles CBE and CDA are congruent.

That is another way of naming triangles ADC and EBC.

Answer: Second choice.

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If we changed our speed limit signs to metric, what would probably replace 45 mi/h? (Please round your answer to the nearest 1 k

lozanna [386]

72km/h because 45 miles equals 72.4205 kilometers. You wouldn’t round up because the tenths decimal place isn’t above 5, so it would be 72 km/h.

7 0

3 years ago

C(x)=2x^3+3x^2-1 find rational zeros

3241004551 [841]

Answer:

1/2

Step-by-step explanation:

The Rational Root Theorem says that any rational root has

1. a numerator that is a factor of the constant term

2. a denominator that is a factor of the leading coefficient (that's attached to the highest-power term)

Numerator: $\pm 1$

Denominator: $\pm 2$

That means there are only two possible rational roots: $\pm \frac{1}{2}$

Try them both by plugging them into the polynomial.

$2\left(\frac{1}{2}\right)^3 + 3\left(\frac{1}{2}\right)^2 -1= \frac{1}{4}+\frac{3}{4}-1 =0$

Aha! The negative one-half value does not produce 0

3 0

3 years ago

Can someone pls help me!! And if u can explain how u do it I will very thankful for that..

Amiraneli [1.4K]

Answer:

For the first question is 8y, and the second question would be 80

Step-by-step explanation:

The perimeter of a shape is calculated by adding it's sides together, and 2y+2y+2y+2y=8y. If y=10, we can substitute y for 10 in which 8*10 is 80.

8 0

3 years ago

Please help on this geometry question

DochEvi [55]

Angles are said to be produced whenever two or more straight lines intersect. Some types of angles are right angle, obtuse angle, acute angle, etc. Thus, the required proof is stated below:

Prove: <A > <C

<D

An obtuse angle is a given angle that is greater than $90^{o}$ but less than $180^{o}$ . While an acute angle is a given angle that is less than $90^{o}$ .

Thus extend AB to F, such that BF = CD.

Draw a perpendicular from a to intersect CD at point E.

So that;

<BAD = <BAE + <DAE (addition property of an angle)

Such that;

<A is an obtuse angle, while <C is an acute angle. Thu,

<A > <C (different types of angles)

Also,

<ADC = <CDF - <ADF (subtraction property of angles)

But both angles B and D are acute angles.

So that;

<C (comparison of measures of two angles)

For more clarifications on types of angles, visit: brainly.com/question/11558730

#SPJ1

5 0

2 years ago

Make r the subject P=10(q-3r)/r

katen-ka-za [31]

4r=10q/P I do believe
P=10(q-3r)/r
(r) (r)
Pr=10(q-3r)
/10 /10
Pr/10=q-3r
+3r +3r
Pr+3r/10=q
(10) (10)
Pr+3r=10q
/P /P
r+3r= 10q/P
4r=10q/P

8 0

3 years ago