The probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333 is <u>0.08325</u>. Hence, <u>option C</u> is the right choice.
For any two events A and B, the probability of event A and B, that is, P(A ∩ B) is given as:-
- When the events are dependent, P(A ∩ B) = P(A).P(B|A).
- When the events are independent, P(A ∩ B) = P(A).P(B).
In the question, we asked the probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333.
We know that when the events are independent, P(A ∩ B) = P(A).P(B).
Thus, P(A ∩ B) = (0.25)*(0.333),
or, P(A ∩ B) = 0.08325.
Thus, the probability P(ANB), that is, P(A ∩ B), given that A and B are independent events and P(A) = 0.25 and P(B) = 0.333 is <u>0.08325</u>. Hence, <u>option C</u> is the right choice.
Learn more about the probability of independent events at
brainly.com/question/12783373
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