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matrenka [14]
3 years ago
8

C(x)=2x^3+3x^2-1 find rational zeros

Mathematics
1 answer:
3241004551 [841]3 years ago
3 0

Answer:

1/2

Step-by-step explanation:

The Rational Root Theorem says that any rational root has

1. a numerator that is a factor of the constant term

2. a denominator that is a factor of the leading coefficient (that's attached to the highest-power term)

Numerator:  \pm 1

Denominator: \pm 2

That means there are only two possible rational roots: \pm \frac{1}{2}

Try them both by plugging them into the polynomial.

2\left(\frac{1}{2}\right)^3 + 3\left(\frac{1}{2}\right)^2 -1= \frac{1}{4}+\frac{3}{4}-1 =0

Aha!  The negative one-half value does not produce 0

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In the ordered pair (-12,-6) what is the x-coordinate?
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Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy
Margaret [11]

Answer:

Part 1) The exact solutions are

(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})   and  (\frac{-1-\sqrt{21}} {2},4-\sqrt{21})

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

y=x^{2} +3x ----> equation A

y=2x+5 ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

<em>Find the exact solutions of the system</em>

equate equation A and equation B

x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +x-5=0  

so

a=1\\b=1\\c=-5

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}

x=\frac{-1\pm\sqrt{21}} {2}

so

The solutions are

x_1=\frac{-1+\sqrt{21}} {2}

x_2=\frac{-1-\sqrt{21}} {2}

<em>Find the values of y</em>

<em>First solution</em>

For x_1=\frac{-1+\sqrt{21}} {2}

y=2(\frac{-1+\sqrt{21}} {2})+5

y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}

The first solution is the point (\frac{-1+\sqrt{21}} {2},4+\sqrt{21})

<em>Second solution</em>

For x_2=\frac{-1-\sqrt{21}} {2}

y=2(\frac{-1-\sqrt{21}} {2})+5

y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}

The second solution is the point (\frac{-1-\sqrt{21}} {2},4-\sqrt{21})

Round to the nearest hundredth

<em>First solution </em>

(\frac{-1+\sqrt{21}} {2},4+\sqrt{21}) -----> (1.79,8.58)

(\frac{-1-\sqrt{21}} {2},4-\sqrt{21}) -----> (-2.79,-0.58)

see the attached figure to better understand the problem

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The sum of 3x^2 -8x -2 and 4x -2 is?
Lady_Fox [76]

Answer:

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Step-by-step explanation:

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=3x^2+−8x+−2+4x+−2

3x^2+−8x+−2+4x+−2

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=3x^2+−4x+−4

7 0
3 years ago
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