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ludmilkaskok [199]

3 years ago

8

If x= 12, what is the value of 3(x - 3)? OA. 27 OB. 33 OC. 45 OD. 9

2 answers:

kompoz [17]3 years ago

8 0

3(12-3)
Expand
36-9
Which is 27

GalinKa [24]3 years ago

6 0

Answer:

27

Step-by-step explanation:

3 (12 - 3)

multiply 3 *12 = 36

multiply 3 * 3 = 9

36-9 =27

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*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

A black tailed Jackrabbit hops about 7 feet in a single hop how far can it hop in 5 seconds

Sever21 [200]

If it hops 7 feet a second then it would hop 35 times in 5 seconds. 5 x 7 = 35.

Happy studying ^-^

6 0

3 years ago

Read 2 more answers

Julie built a tower of blocks that stood 22.5 cm tall. Each block is 1.5 cm tall. How many blocks are in the tower? A. 16 B. 15

sergejj [24]

22.5 cm* (1 block/ 1.5 cm)= 15 blocks.

The correct answer is B. 15~

7 0

3 years ago

Read 2 more answers

How can you use a 10-by-10 grid to model 12%? You can shade half of the squares. You can shade half of one row of the squares. Y

TiliK225 [7]

Answer:

The options provided do not have the correct answer. Read below.

Step-by-step explanation:

Given a 10 by 10 grid model means that there are exactly 100 individual squares present. This shows that each square is equal to 1%.

None of the options provided gives us 12% of the model.

The first option results in 50%, the second results in 5%, third option results in 0.5% and the last option results in 2%.

For 12% we can shade 12 squares completely, half of 24 squares etc.

I hope this answer helps.

3 0

3 years ago

In a chess club the probability that Shaun will beat Mike is 3/8 .

romanna [79]

Answer:

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So $1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8}$ probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So $1 - \frac{5}{7} = \frac{2}{7}$ probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

$p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786$

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

3 0

3 years ago