If it's mutiple choice can I see the options :) would make this easier
Answer:
James bought 11 good tickets and 5 bad tickets.
Step-by-step explanation:
Given that:
Cost of each good ticket = $8
Cost of each bad ticket = $5
Total amount spent = $113
Total tickets bought = 16
Let,
x be the number of good tickets bought
y be the number of bad tickets bought
x+y=16 Eqn 1
8x+5y=113 Eqn 2
Multiplying Eqn 1 by 5
5(x+y=16)
5x+5y=80 Eqn 3
Subtracting Eqn 3 from Eqn 2
(8x+5y)-(5x+5y)=113-80
8x+5y-5x-5y=33
3x=33
Dividing both sides by 3

Putting x=11 in Eqn 1
11+y=16
y=16-11
y=5
Hence,
James bought 11 good tickets and 5 bad tickets.
Answer:
=12
Step-by-step explanation:
7=3(0)-5
7=-5
7+5
=12
Im pretty sure this is the answer
3/5 is greater because the decimal is .6 while 21/40 is .525
Answer:
3 multiply by 6 multiply by 5
= 90 cm²