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frozen [14]
3 years ago
11

Simplify by combining like terms Х 10k +5 +2k

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0
10+2k+5
12k+5

Give the other person Brainly
Arte-miy333 [17]3 years ago
5 0
Answer: 12k + 5
Hope this helps:)
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The total cost of 1 pencil and 2 erasers is £8, and the total cost of 2 pencils and 4 erasers is £20, as shown below:
Paul [167]

Answer:

see explanation

Step-by-step explanation:

The 2 equations are

x + 2y = 8 → (1)

2x + 4y = 20 → (2)

8 0
2 years ago
Select the statement that describes this expression: (10 − 3) x 4 + 5.
swat32

Answer:

c. (Multiply 4 by the difference of 10 and 3, then add 5)

5 0
2 years ago
Determine the measure of angle BZC.
dusya [7]

Answer:

70 degrees

Step-by-step explanation:

Angle BZA = Angle BZC = 20 degrees

Reason : These two angles are Vertically opposite angles.

Angle BZA + Angle BZC = 90

20 + Angle BZC = 90

Angle BZC = 90 - 20

Angle BZC = 70 degrees

8 0
3 years ago
A television station is interested in predicting whether or not voters are in favor of an increase in the state sales tax. It as
slamgirl [31]

Answer: (C) the 2633 viewers who phoned in.

Step-by-step explanation:

In statistics , a sample is a countable subset of a large population that represents the entire population.

Given : A television station is interested in predicting whether or not voters are in favor of an increase in the state sales tax.

It asks its viewers to phone in and indicate whether they support or are opposed to an increase in the state sales tax in order to generate additional revenue for education.

Of the 2633 viewers who phone in, 1474 (55.98%) are opposed to the increase.

i.e. 1474 out of 2633 viewers opposed to the increase.

Clearly , 2633 viewers are representing the entire population of viewers.

Hence, the sample obtained is the 2633 viewers who phoned in.

8 0
3 years ago
Determine the zeroes of the polynomial
Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)}  \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)}  -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\

\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}

8 0
3 years ago
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