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anastassius [24]
3 years ago
15

What is the expression in factored form?x^2+13x+14

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

Step-by-step explanation:

To factor the expression x^2+13x+14 you need to know its roots.

First find the discriminant of this quadratic polynomial:

D=13^2-4\cdot 1\cdot 14=169-56=113.

Then the roots of the expression x^2+13x+14 are

x_{1,2}=\dfrac{-13\pm \sqrt{113}}{2}.

Now the factored form is

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

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This question is incomplete, the complete question is;

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Write down the cost function C, marginal cost function C’, and average cost function

Answer:

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- the marginal cost function is 1,900,000 - (80000 /√x  )

- The  average cost function is 1,900,000 + [ 500,000 / x ] - [ 160,000 / √x ]

Step-by-step explanation:

Given the data in the question;

cost per spot = $1.9 million

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discount = $160,000√x

 Let C(x) represent the cost ;

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Cost x television spot = $1.9 million × x

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Therefore, The  the cost function is 500,000 + 1,900,000x - 160,000√x

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Cost function C(x) = 500,000 + 1,900,000x - 160,000√x

we differentiate with respect to x

C'(x) = d/dx( 500,000 + 1,900,000x - 160,000√x )

= d/dx( 500000 ) + 1,900,000d/dx -160,000 d/d( √x )

= 0+ 1,900,000(1) -160,000( 1 / 2√x )

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= 1,900,000 - (80000 /√x  )

Therefore, the marginal cost function is 1,900,000 - (80000 /√x  )

Average cost function;

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we substitute

Average cost function = [500,000 + 1,900,000x - 160,000√x] / x

=  [500,000 / x ] + [1,900,000x / x ]  - [ 160,000√x / x ]

=  [ 500,000 / x ] + 1,900,000 - [ 160,000√x / x ]

=  1,900,000 + [ 500,000 / x ] - [ 160,000 / √x ]

Therefore, The average cost function is 1,900,000 + [ 500,000 / x ] - [ 160,000 / √x ]

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