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anastassius [24]
3 years ago
15

What is the expression in factored form?x^2+13x+14

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

Step-by-step explanation:

To factor the expression x^2+13x+14 you need to know its roots.

First find the discriminant of this quadratic polynomial:

D=13^2-4\cdot 1\cdot 14=169-56=113.

Then the roots of the expression x^2+13x+14 are

x_{1,2}=\dfrac{-13\pm \sqrt{113}}{2}.

Now the factored form is

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

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The nth term of this sequence is ansquared+by+c<br> 1,11,27,49 <br> Find the values of a b and c
stiv31 [10]

Answer:

The values of a, b and c are:

  • a = 3
  • b = 1
  • c = -3

Step-by-step explanation:

Step 1:

First Confirm the sequence is quadratic by finding the second difference.

Sequence = 1,11,27,49

1st difference:

  • 11-1=10
  • 27-11=16
  • 49-27=22

2nd difference:

  • 16-10=6
  • 22-16=6

Step 2:

Just divide the second difference by 2, you will get the value of a.

6 ÷ 2 = 3

So the first term of the nth term is 3n^{2}

Step 3: Next, substitute the number 1 to 5 into  3n^{2}

n = 1,2,3,4,5

3n² = 3,12,27,48,75

Step 4:

Now, take these values (3n²) from the numbers in the original number sequence and work out the nth term of these numbers that form a linear sequence.

n = 1,2,3,4,5

3n² = 3,12,27,48,75

Differences:

1 - 3 = -2

11 - 12 = -1

27 - 27 = 0

49 - 48 = 1

Now the nth term of these differences (-2,-1,0,1) is (n - 1) - 2.

so b = 1, and c = -3

Step 5: Write down your final answer in the form an² + bn + c.

3n² + (n - 1) -2

= 3n² + n - 1 - 2

= 3n² + n - 3

Therefore, the values of a, b and c are:

  • a = 3
  • b = 1
  • c = -3
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4 years ago
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