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anastassius [24]
3 years ago
15

What is the expression in factored form?x^2+13x+14

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

Step-by-step explanation:

To factor the expression x^2+13x+14 you need to know its roots.

First find the discriminant of this quadratic polynomial:

D=13^2-4\cdot 1\cdot 14=169-56=113.

Then the roots of the expression x^2+13x+14 are

x_{1,2}=\dfrac{-13\pm \sqrt{113}}{2}.

Now the factored form is

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

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the midpoint is AB is M(3,-2). One endpoint is A(7,-9). Find the coordinates of the other endpoint B.
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<em>The required points of the given line segment  are ( - 1, - 5 ).</em>

Step-by-step explanation:

Given that the line segment AB whose midpoint M is ( 3, -2 ) and point A is ( 7, - 9), then we have to find point B of the line segment AB -

As we know that-

If a line segment AB is with endpoints ( x_{1}, y_{1} ) and  ( x_{2}, y_{2}  )then the mid points M are-  

<em>M = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2}  }{2}  )</em>

Here,

<em>Let A ( 7, - 9 ), B ( x, y ) with midpoint M ( 3, - 2 ) -</em>

then by the midpoint formula M are-

<em>( 3, - 2 )  = ( \frac{ 7 + x}{2} , \frac{ - 9 + y}{2} )</em>

On comparing x coordinate and y coordinate -

We get,

<em>( \frac{ 7 + x}{2} = 3  , \frac{ - 9 + y}{2}  = - 2)</em>

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<em>( x = - 1, y = -5 )</em>

<em>Hence the required points  A are ( - 1, - 5 ).</em>

<em>We can also verify by putting these points into Midpoint formula.</em>

<em />

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