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anastassius [24]
3 years ago
15

What is the expression in factored form?x^2+13x+14

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

Step-by-step explanation:

To factor the expression x^2+13x+14 you need to know its roots.

First find the discriminant of this quadratic polynomial:

D=13^2-4\cdot 1\cdot 14=169-56=113.

Then the roots of the expression x^2+13x+14 are

x_{1,2}=\dfrac{-13\pm \sqrt{113}}{2}.

Now the factored form is

\left(x-\dfrac{-13+\sqrt{113}}{2}\right)\left(x-\dfrac{-13-\sqrt{113}}{2}\right).

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Answer:

The answer to your question is below

Step-by-step explanation:

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a) From the graph we got  f(-1) = -5

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5 0
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Answer:

6 mins

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5 0
3 years ago
Read 2 more answers
Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or
WARRIOR [948]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\



\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8

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