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neonofarm [45]
3 years ago
12

Find the solution of 5 times the square root of the quantity of x plus 7 equals negative 10, and determine if it is an extraneou

s solution
Mathematics
2 answers:
likoan [24]3 years ago
8 0

we are given

5 times the square root of the quantity of x plus 7

so, we get

left side is

5\sqrt{x+7}

right side is -10

so, we can set them equal

5\sqrt{x+7}=-10

Since, we have to solve for x

so, we will isolate x one anyone side

and then we can solve for x

we take square both sides

(5\sqrt{x+7})^2=(-10)^2

25(x+7)=100

Divide both sides by 25

\frac{25(x+7)}{25} =\frac{100}{25}

x+7 =4

Subtract both sides by 7

x+7-7 =4-7

x =-3

Extraneous solution:

we can plug x=-3 into original

5\sqrt{-3+7}=-10

5\sqrt{4}=-10

5*2=-10

10=-10

we know that 10 is not equal to -10

so, x=-3 is not valid solution

Hence, this is extraneous solution...........Answer

Leto [7]3 years ago
6 0
The solution of the information given will be as follows:
5√(x+7)=10
dividing both sides by 5 we get:
√(x+7)=2
squaring both sides we get:
(x+7)=2²
x+7=4
solving for x we get
x=4-7
x=-3
thus the answer is x=-3
this is an extraneous solution.<span />
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3 years ago
Help with both questions please
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Can i get some help i suck at this lol
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3 years ago
Identify the center and radius for the circle with the following equation; (x+5)^2+y^2+12y=3
rosijanka [135]
Center: (-5,-6)
Radius: 39
How to do it

Complete the square for
y
2
+
12
y
y
2
+
12
y
.

(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
Substitute
(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
for
y
2
+
12
y
y
2
+
12
y
in the equation
(
x
+
5
)
2
+
y
2
+
12
y
=
3
(
x
+
5
)
2
+
y
2
+
12
y
=
3
.
(
x
+
5
)
2
+
(
y
+
6
)
2
−
36
=
3
(
x
+
5
)
2
+
(
y
+
6
)
2
-
36
=
3
Move
−
36
-
36
to the right side of the equation by adding
36
36
to both sides.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
Add
3
3
and
36
36
.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
This is the form of a circle. Use this form to determine the center and radius of the circle.
4 0
3 years ago
Which is equivalent to 64 Superscript one-fourth?
Schach [20]

Answer:

2 RootIndex 4 StartRoot 4 EndRoot

Step-by-step explanation:

we have

64^{\frac{1}{4}}

Decompose the number 64 in prime factors

64=2^{6}=2^{4}2^{2}

substitute

64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}

7 0
3 years ago
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