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kiruha [24]
3 years ago
13

Solve 7+x÷3=2x-5 pls help me with this

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

Answer:

4.4

Step-by-step explanation:

Write the question out as an equation:

7+x/3 = 2x - 5

Rearrange , simplify and solve:

7+x = 3(2x-5) = 6x - 15

7+x = 6x-15

6x - 15 = 7+x

6x = 7+x+15 = 22+x

6x = 22+x

6x-x = 22

5x = 22

x = 4.4

hope this helps.

Good Luck.

Please Mark Brainiest

8090 [49]3 years ago
3 0

Answer:

Step-by-step explanation:

7+x/3=2x-5

taking 3 on the RHS

7+x=6x-15

22=5x

x=22/5

=4.4

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Hat is the value of x in the equation 4 x plus 8 y equals 40, when y equals 0.8? 4.6 8.4 10 12
Elan Coil [88]

Step-by-step explanation:

4x + 8y = 40

4x + (8×0.8) = 40

4x + 6.4 = 40

4x = 33.6

4x÷4 = 33.6 ÷ 4

x = 8.4

6 0
2 years ago
A ^2+b^2=c^2 solve for c
musickatia [10]
Take the root of both sides, and then solve. 
c = sqrt a^2 + b^2, - sqrt a^2 + b^2.

3 0
3 years ago
Which of the following expressions Will result in a product less than zero? Select all that apply
Semmy [17]

Answer:

A and D

Step-by-step explanation:

Negative times positive is always negative, thus making them less than 0. Negative times negative is positive, so B and C both have a positive product. Hope this helps

6 0
2 years ago
NEED HELP ASAP PLEASE AND THHANK YOU!
ad-work [718]

he formula to find area of a triangle is (base × height) ÷ 2


The area of the first triangle = (6 × 2) ÷ 2 = 6

The area of the second triangle = (7 × 3) = 10.5


Total area of the logo is 6+10.5 = 16.5 cm²




4 0
3 years ago
Suppose that you have 7 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards without replace
wlad13 [49]

Answer:

a. 7/22

b. 28/33

c. 7/22

d. dependent events

Step-by-step explanation:

The total number of cards is given as 7 + 5 = 12.

The probability if a card being green on the first pick, P(G) =  7/12

The probability of a card being yellow on the first pick, P(Y) = 5/12

Because there is no replacement, the card are going to be short by one card. Therefore, the second pick will be like this:

P(GG)  = ( 7/12×6/11)

P(GY) = ( 7/12 × 5/11)

P(YG) = ( 5/12×7/11)

P(RR) = ( 5/12 ×4/11)

a. P (G1 and G2) = ( 7/12×6/11)

                          = 7/22

b. P( At least one is green) = ( 7/12×6/11) +  ( 7/12 × 5/11) + ( 5/12×7/11)

                           = 28/33

c. P(G2G1)           = 7/22

d. the events are dependent. They do not give the same result.

6 0
3 years ago
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