Question

What is the product of Three-fourths and Negative StartFraction 6 over 7 EndFraction? -9/14

Answer 1

Answer:

The product is :  $-\frac{9}{14}$

Step-by-step explanation:

First term given to us is =  $\frac{3}{4}$

Second term given to us = $-\frac{6}{7}$

We have to find product for term 1 and term 2

Which means that we have to find : $(\frac{3}{4})\cdot(-\frac{6}{7})$

Calculating the product of fraction is pretty simple. To calculate the product of any two fractions. We have to multiple the numerator of 1st term with numerator of 2nd which serves as the the numerator of the product. Similarly we have to multiply denominator with denominator.

$(\frac{3}{4})\cdot(-\frac{6}{7}) = \frac{3\cdot(-6)}{4\cdot7} = -\frac{18}{28}$

Reduce the fraction

$-\frac{18}{28}= -\frac{9}{14}$