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SpyIntel [72]
3 years ago
13

What is the product of Three-fourths and Negative StartFraction 6 over 7 EndFraction? -9/14

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

Answer:

The product is :  -\frac{9}{14}

Step-by-step explanation:

First term given to us is =  \frac{3}{4}

Second term given to us = -\frac{6}{7}

We have to find product for term 1 and term 2

Which means that we have to find : (\frac{3}{4})\cdot(-\frac{6}{7})

Calculating the product of fraction is pretty simple. To calculate the product of any two fractions. We have to multiple the numerator of 1st term with numerator of 2nd which serves as the the numerator of the product. Similarly we have to multiply denominator with denominator.

(\frac{3}{4})\cdot(-\frac{6}{7}) = \frac{3\cdot(-6)}{4\cdot7} = -\frac{18}{28}

Reduce the fraction

-\frac{18}{28}= -\frac{9}{14}

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3 years ago
A university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standar
Ad libitum [116K]

Answer:

The Sample Size Need To be at least 114

Step-by-step explanation:

According to the Question,

  • Given, A university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standard deviation from a previous study is 6.2 hours.

The Maximum Error(E) is given as 1.5 hours and the standard deviation(σ) is 6.2 hours.

  • Now, For 99% Confident the level of value α is 0.01.

α/2 = 0.01/2 ⇒ 0.005

  • Thus, From The table, We get that the value of Z_{alpha/2} is 2.58.

Hence, the sample size n can be found as

n = {\frac{(Z_{alpha/2} * Standard Deviation)}{E}}²

n = {2.58 × 6.2}² / 1.5²

n = 113.72 .

So, The Sample Size Need To be at least 114.

4 0
3 years ago
It is cloudy outside. What is the first step of indirectly proving this statement?
Monica [59]
<span>
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6 0
4 years ago
The displacement of a particle from a reference point at any instant is given by s = 3 t 2 - 4 t + 5 , where s is in metres and
lina2011 [118]

The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.

How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t

Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.

To learn more about this, tap on the link below:
brainly.com/question/2234298

#SPJ9

3 0
1 year ago
Pls help I never did this before
maria [59]

Answer:

16 and 64

Step-by-step explanation:

When you sqaure root 16, you get 4

When you cube root 64, you get 4

6 0
3 years ago
Read 2 more answers
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