What is the area of this figure?

ludmilkaskok [199]

Given:

The point (9,-12) is on terminal side of angle theta in standard position.

To find:

The exact value of each of the six trigonometric functions of theta.

Solution:

The given point is (9,-12). Here, x-coordinate is positive and y-coordinate is negative. So, the point lies in 4th quadrant and only cos and sec are positive in 4th quadrant.

We know that,

$r=\sqrt{x^2+y^2}$

$r=\sqrt{9^2+(-12)^2}$

$r=\sqrt{81+144}$

$r=\sqrt{225}$

$r=15$

Now,

$\sin \theta=\dfrac{y}{r}=\dfrac{-12}{15}=-\dfrac{4}{5}$

$\cos \theta=\dfrac{x}{r}=\dfrac{9}{15}=\dfrac{3}{5}$

$\tan \theta=\dfrac{y}{x}=\dfrac{-12}{9}=-\dfrac{4}{3}$

$\cot \theta=\dfrac{1}{\tan \theta}=-\dfrac{3}{4}$

$\text{cosec} \theta=\dfrac{1}{\sin \theta}=-\dfrac{5}{4}$

$\sec \theta=\dfrac{1}{\cos \theta}=\dfrac{5}{3}$

Therefore, the values of six trigonometric functions of theta are $\sin \theta=-\dfrac{4}{5},\cos \theta=\dfrac{3}{5},\tan \theta=-\dfrac{4}{3},\cot \theta=-\dfrac{3}{4},\text{cosec} \theta=-\dfrac{5}{4},\sec \theta=\dfrac{5}{3}$ .

6 0

4 years ago

I need help can someone help me (:

vladimir2022 [97]

Hey there!

To solve the first problem, I've found it easiest to solve the equation for, say, values –2 through +2 and create a table of values for you to begin graphing this function. You may need to do more depending on the equation itself.

Some points are: (–2, 0.75), (–1, 1.5), (0, 3), (1, 6) and (2, 12). You can check which graph matches up with these points the closest to get your answer of D.

To solve the second problem, you'll need to use the distance equation.

x1 = –4, y1 = 3
x2 = –1, y2 = 1
___________________
√ (x2–x1)^2 + (y2–y1)^2
_________________
√ (–1–(–4)^2 + (1–3)^2
_______________
√ (–1+4)^2 + (–2)^2
____________
√ (3)^2 + (–2)^2
_____
√ 9 + 4
___
√ 13, making your answer D

For your third question, I always just counted the number of units the point was from the line of reflection. You'll count twice diagonally towards the line from point C for this one, staying on the "crosshairs" of the graph. All you need to do then is count two diagonal units along the same line, then you'll get your answer of (2, 6), or D.

For your final question, A and B are immediately out, since they won't be parallel to the 4x equation. You'll need to solve both of your remaining equations for y with 2 plugged in for x; whichever one equals 7 will be your answer. In this case, it will be D.

Hope this helped you out! :-)

3 0

3 years ago

Wayne went on a 4km hike. He took a break at 4/3 k. He took a drink of water at 10/3. Show Wayne's hike on the number line. Incl

tamaranim1 [39]

1. The information given in this problem, is:

- <span>Wayne went on a 4 km hike.
- </span>Wayne took a break at 4/3 km.
- Wayne took a drink of water at 10/3.

2. Then, when you convert the values from fractions to decimals, you have:

4/3 km=1.33 km
10/3 km=3.33 km

3. With this values, you can make the number line and show <span>his starting and finishing place, and the 2 points where he stopped. This is shown in the figure attached.</span>