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Butoxors [25]
3 years ago
15

The work that Yi did to find the greatest common factor of 42 and 63 is shown below. Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42 Fa

ctors of 63: 1, 7, 9, 63 The greatest common factor is 7. What is Yi’s error? Yi did not list all the factors of 63. Yi listed multiples for each number instead of factors. Yi did not list all the factors of 42. Yi found the least common multiple.
Mathematics
2 answers:
MariettaO [177]3 years ago
6 0

Answer:

A. Yi did not list all the factors of 63

Step-by-step explanation:

Did the quiz

Verizon [17]3 years ago
4 0

Answer:

A Yi did not list all of the factors of 63

Step-by-step explanation:

hope this helps

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Find each. a. za_2 for the 99% confidence interval b. za_2 for the 98% confidence interval c. za_2 for the 95% confidence interv
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b) Z = 2.327.

c) Z = 1.96.

d) Z = 1.645.

e) Z = 1.88.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Question b:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Question c:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Question d:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Question e:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.94}{2} = 0.03

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.03 = 0.97, so Z = 1.88.

8 0
3 years ago
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