Answer:
Speed of second car will be 57.17 m/sec
Explanation:
We have given lead car travels = 44 laps
1 laps = 1.34 km = 1340 m
So total distance = 1340×44 = 58960 m
Speed of lead car = 55.9 m/sec
We know that 
As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m
So speed of second car will be 
Answer:
light travels in a straight line
Explanation:
the others are wrong
Answer:
a) Her average speed was 0.778 km/min
b) Her average velocity was 0.572 km/min
Explanation:
a) The average speed is given by the traveled distance over time:
average speed = distance / time
average speed = 14.0 km / 18.0 min = 0.778 km/min
b) The average velocity is given by the displacement over time. It is calculated as the variation of the position over time relative to the frame of reference. In this case, the origin of the frame of reference is located at the home of the student. The final position will be the university. Then:
velocity = (final position - initial position)/ time
velocity = 10.3 km / 18.0 min = 0.572 km/min
Answer:
Part a)

Part b)
Magnitude of the force is given as

Part c)
As we know that Y component of the force is negative so here the force is directed below the X axis

Explanation:
Part a)
Adrienne apply the force of 20 N along +X direction and Jim apply force of 40 N at 53 degree above negative X axis
so we will have



now let say the force exerted by Luis is F such that sum of all forces must be zero
now we have

so we have



Part b)
Magnitude of the force is given as


Part c)
As we know that Y component of the force is negative so here the force is directed below the X axis
So here we have

