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Nataly_w [17]
3 years ago
11

Write a paragraph that explains how a droplet of water that falls as rain can move through the atmosphere, the biosphere, the ge

osphere, and the hydrosphere. Be specific as you explain the processes (evaporation, condensation, transpiration) that occur because of interaction between Earth’s spheres.
In your response, be sure to…
• Give the state of matter that water is in as it moves through Earth’s systems
• Describe what processes occur to change water from one state of matter to another
Physics
2 answers:
True [87]3 years ago
7 0
The water cycle starts with evaporation. It is a process where water at the surface turns into water vapors. Water absorbs heat energy from the sun and turns into vapors. Water bodies like the oceans, the seas, the lakes, and the river bodies are the main source of evaporation. Through evaporation water  moves from hydrosphere to atmosphere.
seropon [69]3 years ago
5 0

Answer:

Water vapor becomes liquid with the condensation process.Water from lakes and rivers is evaporated into the atmosphere.Water from living organisms is released through the transpiration process. It is explained in the explanation section.

Explanation:

We need to explain How water falls as rain and can move through the atmosphere, the biosphere, geosphere, and hydrosphere.

First Step: water is under condensation process, water vapor from the atmosphere transform in liquid, due to the weight and the weather conditions, liquid water will fas as rain. When water falls, we have two possible ways:

1- If waterfalls directly into a water source such as rivers, water will continue its cycle in liquid phase through the hydrosphere. Finally, the river should arrive at the sea. Water from the sea can be evaporated again and return to the atmosphere.

2- If water falls into the ground, geosphere or Biosphere. The water inside the ground can be taken by plants through their roots, so, water pass from the geosphere to the biosphere.

Finally, living organisms such as animals, humans, and plants can drink water through the mouth, the roots or the specialized organ. Water is released to the atmosphere through transpiration process of every single living organism. 

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Shutting the fluid discharge of an air-operated reciprocating pump will cause the pump to ?
Misha Larkins [42]
Had to look for the options and here is my answer. What happens when the fluid discharge of an air-operated reciprocating pump is shut, this will cause the pump to OVERSTROKE. Overstroke happens when the engine is switching in a normally-closed manner.  
8 0
4 years ago
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6. The hole on a level, elevated golf green is a horizontal distance of 150 m from the tee and at an elevation of 12.4 m above t
Georgia [21]

Answer:

u = 104.68 m/s

Explanation:

given,

horizontal distance = 150 m

elevation of  12.4 m

angle = 8.6°

horizontal motion = x = u cos θ. t .............(1)

vertical motion =

y = u sin \theta - \dfrac{1}{2}gt^2................(2)

from equation(1) and (2)

y = x tan \theta - \dfrac{gx^2}{2u^2cos^2\theta}..........{3}

12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}

\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29

\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2

u = \sqrt{10959.34}

u = 104.68 m/s

The initial speed of the ball is u = 104.68 m/s

8 0
3 years ago
A car is traveling with a velocity of 5.5 m/s and has a mass of 1200 kg. What is the kinetic energy?!
vesna_86 [32]

Answer:

<h2>18150 J</h2>

Explanation:

The kinetic energy of the car can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the Mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1200 \times  {5.5}^{2}  \\  = 600 \times 30.25

We have the final answer as

<h3>18150 J</h3>

Hope this helps you

3 0
3 years ago
The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is
astraxan [27]

Complete question:

Point charges q1=- 4.10nC and q2=+ 4.10nC are separated by a distance of 3.60mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30×10−9 N⋅m ? Express your answer in newtons per coulomb to three significant figures.

Answer:

The magnitude of this field is 826 N/C

Explanation:

Given;

The torque exerted on the dipole, T = 7.3 x 10⁻⁹ N.m

PEsinθ = T

where;

E is the magnitude of the electric field

P is the dipole moment

First, we determine the magnitude dipole moment;

Magnitude of dipole moment = q*r

P = 4.1 x 10⁻⁹ x 3.6 x 10⁻³ = 1.476 x 10⁻¹¹ C.m

Finally, we determine the magnitude of this field;

E = \frac{T}{P*sin(\theta)}=  \frac{7.3 X 10^{-9}}{1.476X10^{-11}*sin(36.8)}\\\\E = 825.6 N/C

E = 826 N/C (in three significant figures)

Therefore, the magnitude of this field is 826 N/C

6 0
3 years ago
The amount of the lighted side of the moon you can see is the same during
attashe74 [19]

<u>Answer:</u>

The amount of the lighted side of the moon you can see is the same during "how much of the sunlit side of the moon faces Earth".

<u>Explanation:</u>

The Moon is in sequential rotation with Earth, and thus displays the Sun, the close side, always on the same side. Thanks to libration, Earth can display slightly greater than half (nearly 59 per cent) of the entire lunar surface.

The side of the Moon facing Earth is considered the near side, and the far side is called the reverse. The far side is often referred to as the "dark side" inaccurately but it is actually highlighted as often as the near side: once every 29.5 Earth days. During the New Moon the near side becomes blurred.

5 0
3 years ago
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