A race car is one lap behind the lead race car when the lead car has 44 laps to go in a race. If the speed of the lead car is 55
1 answer:
Answer:
Speed of second car will be 57.17 m/sec
Explanation:
We have given lead car travels = 44 laps
1 laps = 1.34 km = 1340 m
So total distance = 1340×44 = 58960 m
Speed of lead car = 55.9 m/sec
We know that
As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m
So speed of second car will be
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Answer:
η = 58.8%
Explanation:
Work is defined as the force applied by the distance traveled by the body.
where:
W = work [J] (units of joules)
F = force = 294 [N]
d = distance = 5 [m]
Efficiency is defined as the energy required to perform an activity in relation to the energy actually added to perform some activity. This can be better understood by means of the following equation.
Answer:
1752.14 tonnes per year.
Explanation:
To solve this exercise it is necessary to apply the concepts related to power consumption and power production.
By conservation of energy we know that:
Where,
Production of Power
Consumption of power
Where the production of power would be,
Where,
m = Total mass required
Energy per Kilogram
Efficiency
The problem gives us the aforementioned values under a production efficiency of 45%, that is,
Replacing the values we have,
Solving for m,
We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,
tonnes per year.