Question

A race car is one lap behind the lead race car when the lead car has 44 laps to go in a race. If the speed of the lead car is 55.9 m/s, what must be the average speed of the second car to catch the lead car just before the end of the race (i.e., right at the finish line)? Assume 1 lap is 1.34 km. Answer in units of m/s

Answer 1

Answer:

Speed of second car will be 57.17 m/sec

Explanation:

We have given lead car travels = 44 laps

1 laps = 1.34 km = 1340 m

So total distance = 1340×44 = 58960 m

Speed of lead car = 55.9 m/sec

We know that $time=\frac{distance}{speed}=\frac{58960}{55.9}=1054.74sec$

As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m

So speed of second car will be $speed=\frac{distance}{time }=\frac{60300}{1054.74}=57.17m/sec$