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chubhunter [2.5K]
3 years ago
7

Can someone help me?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

-3 - 1 = -4; -3 + 1 = -2

44 - 1 = 43; 44 + 1 = 45

-97 - 1 = -98; -97 + 1 = -96

-78 - 1 = -79; -78 + 1 = -77

56 - 1 = 55; 56 + 1 = 57

95 - 1 = 94; 95 + 1 = 96

50 - 1 = 49; 50 + 1 = 51

8 - 1 = 7; 8 + 1 = 9

36 - 1 = 35; 36 + 1 = 37

-89 - 1 = -90; -89 + 1 = -88

-83 - 1 = -84; -83 + 1 = -82

-37 - 1 = -38; -37 + 1 = -36

-14 - 1 = -15; -14 + 1 = -13

86 - 1 = 85; 86 + 1 = 87

2 - 1 = 1; 2 + 1 = 3

-18 - 1 = -19; -18 + 1 = -17

6 - 1 = 5; 6 + 1 = 7

76 - 1 = 75; 76 + 1 = 77

96 - 1 = 95; 96 + 1 = 97

84 - 1 = 83; 84 + 1 = 83

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How do I do this problem
Vilka [71]
Do you mean 7?

You need to multiply each like term differently ( 1. Coefficient, 2. M term, 3. N term, and 4. O term)

1. The coefficients are 4 and 7, and as you have already solved, that equals to 28.

2. The m terms are (m • m) because there is one m in (4mno) and one m in (mn). m • m would equal to m^2.

3. The n terms are (n • n^2 •n) because there is one n in (4mno), n^2 in (7n^2o^2), and one n in (mn). They would equal n^4.

4. The o term would stay as o^2 as there are not other o terms.

To piece it all together, your answer would be 28m^2n^4o^2, or 28 • m ^2 • n^4 • o^2.
7 0
3 years ago
A new automated production process averages 1.4 breakdowns per day. Because of the cost associated with a breakdown, management
dalvyx [7]

Answer:

The required probability is 0.167

Step-by-step explanation:

Consider the provided information.

Let x be the number of breakdown per day.

A new automated production process averages 1.4 breakdowns per day.

λ=1.4

Probability of having three or more breakdowns during a day is:

P(x\geq 3)=1-[f(0)+f(1)+f(2)]

The Poisson probability function is: f(x)=\frac{\lambda^xe^{-\lambda}}{x!}

Therefore the required probability is:

P(x\geq 3)=1-[\frac{\left(1.4^{0}e^{-1.4}\right)}{0!}+\frac{\left(1.4^{1}e^{-1.4}\right)}{1!}+\frac{\left(1.4^{2}e^{-1.4}\right)}{2!}]

P(x\geq 3)\approx1-0.833

P(x\geq 3)=0.167

Hence, the required probability is 0.167

4 0
3 years ago
grandpa has some cows and ducks in his farm. all in all there are 8 heads and 26 legs, how many cows and ducks are in there? sol
butalik [34]

Answer:

5 cows  and 3 ducks

okay well there are 8 heads and each animal has a head meaning that there are a total of 8 organisms in total. Cows have 4 legs and ducks have 2. Lets say that c is cows and d is ducks. You would have the equations ...

c+d=8

4c+2d=26  

well d techniacally = 8-c, so plug in (8-c) for the value of d

4c+2(8-c)=26.      Distribute to get

4c+16-2c

and then add like terms. Soy ou would get

2c+16=26.

then just isolate the variable but subtracting 16 from both sides and dividing 2 on both sides. The answer you would get is that c=5 so there are 5 cows. Plug in 5 for c so you get 5+d=8 and tadaaaa you subtract 5 from both sides to get that there are 3 ducks.

hope this helps :)

7 0
4 years ago
Diego took a 20 question quiz and earned a 75% on it.
enot [183]

Answer:

He got 5 questions wrong so he scored a 75%

Step-by-step explanation:

I hope this helps :)

8 0
3 years ago
Read 2 more answers
Jared's battery has 4/25 percent of life left. Edward's battery has 3/25 percent of life left. Who has the most battery life lef
love history [14]

Answer:

Jared

Step-by-step explanation:

4/25 is larger than 3/25

5 0
3 years ago
Read 2 more answers
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