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chubhunter [2.5K]
3 years ago
7

Can someone help me?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

-3 - 1 = -4; -3 + 1 = -2

44 - 1 = 43; 44 + 1 = 45

-97 - 1 = -98; -97 + 1 = -96

-78 - 1 = -79; -78 + 1 = -77

56 - 1 = 55; 56 + 1 = 57

95 - 1 = 94; 95 + 1 = 96

50 - 1 = 49; 50 + 1 = 51

8 - 1 = 7; 8 + 1 = 9

36 - 1 = 35; 36 + 1 = 37

-89 - 1 = -90; -89 + 1 = -88

-83 - 1 = -84; -83 + 1 = -82

-37 - 1 = -38; -37 + 1 = -36

-14 - 1 = -15; -14 + 1 = -13

86 - 1 = 85; 86 + 1 = 87

2 - 1 = 1; 2 + 1 = 3

-18 - 1 = -19; -18 + 1 = -17

6 - 1 = 5; 6 + 1 = 7

76 - 1 = 75; 76 + 1 = 77

96 - 1 = 95; 96 + 1 = 97

84 - 1 = 83; 84 + 1 = 83

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I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

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3 years ago
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