Answer:
CH2FCH2F > CH2ClCH2Cl > CH2BrCH2Br
Explanation:
As above, we are comparing:
1, 2 - Difluoloroethane
1, 2 - Dicholoroethane
1, 2 - Dibromoroethane
The three compounds are both in the homologous series with the general formula CnH2n+2X
Where X is the halogen element.
As we go down the periodic table ie fluorine, chlorine, bromine; one electron shell is continuously added to the molecule so therefore bond length between C-X increases. Note that bond length is inversely proportional to bond strength because the shorter the bond length, the stronger the bond.
Also, as more electron shells are added to the halogens down the group, the more further away from the nucleus which gives rise to bond order; the more electrons participate in a bond, the shorter the bond.
In conclusion, the C-F is has the shortest bond and the strongest bond strength.
C-F > C-Cl > C-Br (decreasing bond strength or bond dissociation energy)
CH2FCH2F > CH2ClCH2Cl > CH2BrCH2Br
