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jeyben [28]
3 years ago
8

#1: Which scientist is credited with developing the orbital model of the atom?

Chemistry
1 answer:
CaHeK987 [17]3 years ago
4 0
<span>Niels Henrik David Bohr is the scientist credited with developing the orbital model of the atom. He was Danish physicist who made foundational contributions to understanding atomic structure and quantum theory. He received the Nobel Prize in Physics in 1922</span>
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If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul
bazaltina [42]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

<span>P2 = P1V1/V2</span>

<span>
</span>

<span>The correct answer is the first option. Pressure would increase. This can be seen from the equation above where V2 is indirectly proportional to P2.</span>

8 0
3 years ago
Read 2 more answers
A gas occupies a 1.5 L container at 25 degrees Celsius and 2.0 atm. If the gas is transferred to a 3.0 L container at the same t
harkovskaia [24]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1 x V1 / V2

P2 = 2.0 x 1.5 / 3

<span>P2 = 1 atm</span>

4 0
3 years ago
Read 2 more answers
What is the molarity of the solution with a volume of 23.47 Liters and 14.968 moles?
MrMuchimi

Answer:

0.6378 M

Explanation:

Molarity is defined by Moles per liter.

Plugging the given information in, we get (14.968 moles)/(23.47 L) which comes out to be about 0.6378 M

3 0
3 years ago
The diagram below shows the energy conversions of the Krebs cycle, which is part of cellular respiration. The U-shaped
Jobisdone [24]
The answer to your problem is B
8 0
3 years ago
Read 2 more answers
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
2 years ago
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